All categories

3 years ago

Is brass a heterogeneous or homogeneous mixture ??????

Chemistry

2 answers:

MAXImum [283]3 years ago

6 0

Answer:

Brass is an alloy made up of uniform composition of copper and zinc. It is a homogeneous mixture in which zinc and copper can be varied to create a range of brasses with varying properties.

Explanation:

Hope it helps jenita or jeni , ya jenny

Lynna [10]3 years ago

4 0

Answer:

Brass is a homogenous mixture of copper and zinc

Hope it helped u, plz put thanks

You might be interested in

A gas has a pressure of 760 torr at 21 degrees Celsius. What is the pressure of the gas at 250 degree Celsius.

weeeeeb [17]

Answer:

Given,

P1=760 torr

T1=21°C

T2=250°C

P2=?

Solution,

According to Gay-Lussac's Law or Third Gas Law,

P1T2=P2T1

760×250=21×P2

P2=9047 torr

9047 is the pressure of the gas at 250 degree Celsius.

7 0

3 years ago

Read 2 more answers

How many grams of KNO3 must be dissolved to<br> create 7.25L a 0.200M solution?

timofeeve [1]

Answer:

146.6 g

Explanation:

First we<u> calculate how many KNO₃ moles are there in 7.25 L of a 0.200 M solution</u>, using the <em>definition of molarity</em>:

Molarity = moles / liters

Molarity * liters = moles

0.200 M * 7.25 L = 1.45 moles

Then we<u> convert 1.45 moles of KNO₃ into grams</u>, using its <em>molar mass</em>:

1.45 mol * 101.103 g/mol = 146.6 g

7 0

3 years ago

Ice cream in a bowl with whipped cream and sprinkles is best describe as...

trasher [3.6K]

I think it's a mixture

6 0

3 years ago

Read 2 more answers

Consider the reaction: P(s) + 3/2 Cl2(

AfilCa [17]

K = Ka/Kb

<h3>Further explanation</h3>

<u>Given:</u>

$\boxed{ \ P_{(s)} + \frac{5}{2} Cl_2_{(g)} \rightleftharpoons PCl_5_{(g)} \ \ \ \ \ K_a \ }$
$\boxed{ \ PCl_3_{(g)} + Cl_2_{(g)} \rightleftharpoons PCl_5_{(g)} \ \ \ \ \ K_b \ }$

<u>Question:</u>

Write the equilibrium constant for this reaction:

$\boxed{ \ P_{(s)} + \frac{3}{2} Cl_2_{(g)} \rightleftharpoons PCl_3_{(g)} \ \ \ \ \ K = ? \ }$

in terms of the equilibrium constants, Ka and Kb

<u>The Process:</u>

Let us solve the problem above.

$\boxed{ \ P_{(s)} + \frac{5}{2} Cl_2_{(g)} \rightleftharpoons PCl_5_{(g)} \ \ \ \ \ K_a \ }$ ... (Equilibrium-1)

$\boxed{ \ PCl_3_{(g)} + Cl_2_{(g)} \rightleftharpoons PCl_5_{(g)} \ \ \ \ \ K_b \ }$ ... (Equilibrium-2)

Consider the reaction: $\boxed{ \ P_{(s)} + \frac{3}{2} Cl_2_{(g)} \rightleftharpoons PCl_3_{(g)} \ \ \ \ \ K = ? \ }$

Equilibrium-2 is reversed to match the target reaction (Hint: PCl₃). Then the two equilibrium reactions are added together.

$\boxed{ \ P_{(s)} + \frac{5}{2} Cl_2_{(g)} \rightleftharpoons PCl_5_{(g)} \ \ \ \ \ K_a \ }$ ... (Equilibrium-1)

$\boxed{ \ PCl_5_{(g)} \rightleftharpoons PCl_3_{(g)} + Cl_2_{(g)} \ \ \ \ \ \frac{1}{K_b} \ }$ ... (Equilibrium-2, after reversed)

---------------------------------------------------------------- (+)

$\boxed{ \ P_{(s)} + \frac{3}{2} Cl_2_{(g)} \rightleftharpoons PCl_3_{(g)} \ \ \ \ \ K = K_a \times \frac{1}{K_b} \ }$

<u>Notes:</u>

$\boxed{PCl_5}$ is eliminated.
$\boxed{\frac{5}{2}Cl_2 \ subtracted \ by \ Cl_2 \ equal \ to \ \frac{3}{2}Cl_2}$ .
If the two equilibrium reactions are added together, the equilibrium constants are multiplied by each other.

Thus, the equilibrium constant for the target reaction in terms of the equilibrium constants, Ka and Kb, is

$\boxed{\boxed{ \ P_{(s)} + \frac{3}{2} Cl_2_{(g)} \rightleftharpoons PCl_3_{(g)} \ \ \ \ \ K = \frac{K_a}{K_b} \ }}$

<h3>Learn more</h3>

Conservation of mass brainly.com/question/9473007
About electrolyte and nonelectrolyte solutions brainly.com/question/5404753
How many liters of the 50% solution and how many liters of the 90% solution will be used? brainly.com/question/13034221

Keywords: consider the reaction, P, Cl2, PCl3, PCl5, Ka, Kb, K, write, the equilibrium constant, for this, in terms, reverse, multiply

5 0

4 years ago

Read 2 more answers

Which balance is the centigram balance?<br>1) A<br>2) B

viva [34]

It is B balance, because it has a 0,01 g divisions scale. The minimun division in A balance is only 0,1 g, i.e, decigram measurement.

6 0

3 years ago

Read 2 more answers