Answer:
The answer is in the explanation.
Explanation:
A titration of H₂X with KOH produce:
H₂X + 2KOH → 2H₂O + K₂X
It is possible to obtain the moles of H₂X because the moles of KOH are the spent volume of the titration in liters × 0,455M. As for a complete titration of H₂X moles you need twice moles of KOH you know the moles of KOH obtained are half H₂X moles.
As you know the mass of the solid acid that you titrate and molar mass of acid is:
mass of acid / moles of acid. You can determine the molar mass of the unknown acid.
I hope it helps!
Answer:
2. Copper (II) carbonate plus sulfuric acid produces copper (II) sulfate and carbon dioxide and water.
- We need the "II" after copper to specify what charge it is. It's +2 because carbonate is -2.
3. Calcium hydroxide plus carbon dioxide gas produces calcium carbonate and water.
The correct answer is option 3. A real gas behaves least like an ideal gas under the conditions of high temperature and low pressure. At this temperature and pressure, the molecules are close to each other and collisions or interactions are very likely to happen which is not an ideal gas.
To prepare 350 mL of 0.100 M solution from a 1.50 M
solution, we simply have to use the formula:
M1 V1 = M2 V2
So from the formula, we will know how much volume of the
1.50 M we actually need.
1.50 M * V1 = 0.100 M * 350 mL
V1 = 23.33 mL
So we need 23.33 mL of the 1.50 M solution. We dilute it
with water to a volume of 350 mL. So water needed is:
350 mL – 23.33 mL = 326.67 mL water
Steps:
1. Take 23.33 mL of 1.50 M solution
<span>2. Add 326.67 mL of water to make 350 mL of 0.100 M
solution</span>
