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sergejj [24]
3 years ago
7

Which process represents one chemical change and one physical change

Chemistry
1 answer:
Simora [160]3 years ago
6 0
C. Decomposition is a chemical change and melting is a physical change.
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the balloon is inflated outdoors on a cold day in North Dakota at a temperature of -35°C to a volume of 3.0 L. The pressure rema
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3.75 litres is the volume of the balloon indoors at a temperature of 25°C.

Explanation:

Data given:

initial temperature of the gas in balloon  = -35°C or 238.15 K

initial volume = 3 litres

final temperature = 25 °C  or 298.15 K

final volume =?

pressure remains constant

From the data given when pressure is constant Charles' law is applied.

\frac{V1}{T1} = \frac{V2}{T2}

Rearranging the equation to know the final volume of the gas in balloon

V2 = \frac{V1T2}{T1}

V2 = \frac{3 X 298.15}{238.15}

V2 = 3.75 Litres

when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.

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What is the correct formula (IUPAC) for sodium iodide
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Answer:

The correct formula is...

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Please helpp: All things that are acidic will eventually produce ___ in an aqueous solution?​
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Answer:

Protons / H+ ions

Explanation:

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3 years ago
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Sam's father bought Sam a goldfish and a fish bowl. What must Sam put in the fish bowl so that the goldfish will survive?
KengaRu [80]
Is water because a fish in order  to survive it needs water



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The decomposition of NH4HS is endothermic: NH4HS(s)⇌NH3(g)+H2S(g) Part A Which change to an equilibrium mixture of this reaction
shepuryov [24]

Explanation:

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

As the given reaction is as follows.

       NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)

(a)  When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.

Thus, formation of H_{2}S will increase.

  • (b)  When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.

Hence, formation of H_{2}S will decrease with decrease in volume.

  • When we increase the mount of NH_{4}HS then equilibrium will shift in the direction of decrease in concentration that is, in the forward direction.

Thus, we can conclude that formation of H_{2}S will increase then.

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3 years ago
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