Question

How long would it take to produce enough aluminum to make a case (24 cans) of aluminum soft drink cans if each can used 3 g of aluminum, a current of 5.00 x 104 A was employed, and the current efficiency was 93.9 %?

Answer 1

Answer : It takes time to produce 3 g of aluminium is, 165 seconds.

Explanation :

As we are given that the mass of aluminium is, 3 grams. Now we have to calculate the total mass of aluminum.

Total mass of aluminum = 3g × 24 = 72 g

Now we have to calculate the moles of aluminum.

$\text{Moles of Al}=\frac{\text{Mass of Al}}{\text{Molar mass of Al}}$

Molar mass of Al = 27 g/mol

$\text{Moles of Al}=\frac{72g}{27g/mol}=2.67mol$

As, 1 mole of Al has 3 Faradays

So, 2.67 mole of Al has = $2.67\times 3=80.1$ Faradays

and,

Charge = $80.1\text{ Faradays}\times \frac{96500\text{ coulombs}}{1\text{ Faradays}}=7.73\times 10^6\text{ coulombs}$

Current = $5.00\times 10^4A\times \frac{93.9}{100}=46950A$

Now we have to calculate the time.

$Time=\frac{Charge}{Current}=\frac{7.73\times 10^6}{46950}=164.6s\aaprox 165s$

Hence, it takes time to produce 3 g of aluminium is, 165 seconds.