Answer:
The concentration of the solution is 5.8168 × mol.
Explanation:
Here, we want to calculate the concentration of the solution.
The unit of this is mol/dm^3
So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3
The number of moles = mass/molar mass
molar mass of AlCO3 = 27 + 12 + 3(16) = 27 + 12 + 48 = 87g/mol
Number of moles = 33.4/87 = 0.384 moles
This 0.384 moles is present in 660 L
x moles will be present in 1 dm^3
Recall 1 dm^3 = 1L
x * 660 = 0.384 * 1
x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3
First convert the 112 km/hr ratio into m/s (meters per second). To do this you multiply 112 km with 1000 m/km (since there's 1000 m in one km). You get 112000 m. Then multiply 1 hr with 60 min/hr (since there's 60 min in one hr. You get 60 min, but you want seconds, so multiply 60 min with 60 s/min to get 3600 s. There you go! Your answer is the speed of 112000m/3600s, but you can simplify that to 31.11m/s (since the answer should be in ? meters per 1 second.
Also, the "100-m-distance" part of the question is just to throw you off, because one particular speed obviously stays constant over any distance. Hope that helps :)
Answer:
156.7mL
Explanation:
First we need to find the number of mole of He. This can be achieved by doing the following:
Mass of He from the question = 30g
Molar Mass of He = 4g/mol
Number of mole = Mass /Molar Mass
Number of mole of He = 30/4
Number of mole of He = 7.5moles
Now, we can obtain the volume as follows:
P = 1.15 atm
T = 20°C = 20 + 273 = 293K
R = 0.082atm.L/Kmol
n = 7.5moles
V =?
Recall: PV = nRT
V = nRT/P
V = (7.5 x 0.082 x 293)/1.15
V = 156.7mL
Therefore, the volume that can be filled to that pressure is 156.7mL
Explanation:
What are the two oxidation states of sulphur in sodium thiosulphate ? In thiosulphate, two sulphurs have oxidation state of -2 and +6. (as per suggestions). Sulphur bonded to three oxygen is considered to have +6 (Sulphur A) and other sulphur has -2 (Sulphur B).