Answer:
Following are the solution to this question:
Explanation:
![[H_3O^{+}] =[HCl] \\\\\to [H_3O^{+}] =0.5064 \ m \\\\\to PH =-\log [H_3O^{+}] \\\\](https://tex.z-dn.net/?f=%5BH_3O%5E%7B%2B%7D%5D%20%3D%5BHCl%5D%20%5C%5C%5C%5C%5Cto%20%5BH_3O%5E%7B%2B%7D%5D%20%3D0.5064%20%5C%20m%20%5C%5C%5C%5C%5Cto%20PH%20%3D-%5Clog%20%5BH_3O%5E%7B%2B%7D%5D%20%5C%5C%5C%5C)
The formula of heat added is presented as
Q = m * c * change in (T)
where
Q - the heat added
m - mass
c - specific heat
<span>Change in temperature</span> - (Tf - To)
Basically, in order for us to know the change in heat, the formula is
Change in temperature = T(final) - T(original)
Change in temperature<span> = 36.65 - 24.85
</span>Change in temperature<span> = 11.8 degrees Celcius
</span>
So the change in temperature is 11.8 degrees
Answer:
The answer to your question is 0.6 M
Explanation:
Data
Molarity = ?
Volume = 450 ml
mass of NaCl = 15 g
Process
1.- Calculate the molar mass of NaCl
NaCl = 23 + 35.5 = 58.5 g
2.- Calculate the number of moles of NaCl
58.5 g of NaCl ------------ 1mol
15 g of NaCl ------------ x
x = (15 x 1)/58.5
x = 0.26 moles
3.- Calculate the molarity
Molarity = moles/volume
-Substitutiion
Molarity = 0.26/0.45l
-Result
Molarity = 0.6 M
A:- sn(s) => Sn +2(0.24 M) + 2e-
B:- Sn +2 (0.87 M) +2e- => Sn(s)
solution will become more concentrated and solution B become less concentrated
Sn(s)+ Sn +2(0.87 ) ----> Sn(s) + Sn +2(0.24)
E = Eo - 0.0592 / 2 * log [ (0.24 / 0.87 ) ]
E = 0.0 - 0.0592 / 2 * log ( 0.275)
( n=2 two electrons are transferred)
E = -0.0296 * ( - 0.560)
E = 0.0165 volts
B chemical properties is a right answer
