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denis23 [38]
3 years ago
5

Use the writeln() method of the document object to display the user agent in a tag in the webpage. Hint: The userAgent property

of the window.navigator object contains the user agent.
Engineering
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

Note that writeln() add a new line after each statement

var txt = "<p>User-agent header: " + navigator.userAgent + "</p>";

$("#agent").writeln(txt);

Then Anywhere in the body tag of the html file

create a div tag and include an id="agent"

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The distillation column in Figure 3 is set up for so-called boil-up (V) control. It has
11111nata11111 [884]

A distillation column is an essential item used in the distillation of liquid mixtures to separate the mixture into its component parts, or fractions, based on the differences in volatilities. Fractionating columns are used in small scale laboratory distillations as well as large scale industrial distillations.

3 0
2 years ago
6. At a construction site, cement, sand, and gravel are used to make concrete. The ratio of cement to sand to gravel is 1 to 2.4
S_A_V [24]

Answer:

Mass of cement used is 62.5 lb

Mass of gravel used is 225 lb

Explanation:

The ratio given here is cement to sand to gravel = 1 : 2.4 : 3.6

So, for 150 lb of sand

C : S : G = 1 : 2.4 : 3.6

\frac{C}{S}=\frac{1}{2.4}\\\Rightarrow C=S\frac{1}{2.4}\\\Rightarrow C=150\frac{1}{2.4}\\\Rightarrow C=62.5\ lb

Mass of cement used is 62.5 lb

\frac{S}{G}=\frac{2.4}{3.6}\\\Rightarrow G=S\frac{3.6}{2.4}\\\Rightarrow C=150\frac{3.6}{2.4}\\\Rightarrow C=225\ lb

Mass of gravel used is 225 lb

7 0
3 years ago
In Millikan's oil drop experiment, if the electricfield between the plates was of just the right magnitude, it wouldexactly bala
Vilka [71]

Answer:

The electric field to balance the weight is approximately equals to 3.49x10^5 Newton/Coulumb

Explanation:

In order to be stationary position, magnitude of the total force due to electric field should be equal to the gravitational force that is, |F_{electrostatic}| = |F_{gravitational}|

where

F_{electrostatic}=q.E

where <em>q</em> is the charge of the droplet and E is the electric field. On the other hand

F_{gravitational}=m.g=V.d.g=\frac{4}{3}.\pi.r^3.d.g

where <em>m</em>,<em>V ,d</em> and<em> r</em>  are the mass, volume, density and radius of the oil droplet respectively and <em>g </em>is the gravitational acceleration (g=9,80665 m/sn^2). By using the first equation and solving it for the electric field we can write,

q.E=\frac{4}{3}.\pi.r^3.d.g\\E=\frac{4}{3}.\pi.\frac{r^3.d.g}{q}\\E=\frac{4}{3}.\pi\frac{(1,6x10^{-4})^3.(0,85x10^{-3}).(9,81)}{1,6x10^{-19}}\\E\approx 3,49x10^{5}  (N/C)

(Note: d=0.85 x 10^-3 kg/cm^3 and the unit of electric field is Newton per coulumb (N/C))

8 0
3 years ago
A gas contained within a piston-cylinder assembly, initially at a volume of 0.1 m^3, undergoes a constant-pressure expansion at
NNADVOKAT [17]

Answer:

Q = E + W = 0.25 + 0.4 = 0.29KJ

W = 0.4KJ

b) 2000KJ

Explanation:

The concept applied here is the first law of thermodynamics ,i.e the equation of the first law.

mathematically from first law,

dE = dQ - dW

where E is internal energy

Where energy may be transfereed as eitherf work (W) or heat (Q)

Work on the other hand can be at constant volume and pressure.

at constant pressure, W = Integral (pdV), with final volume(Vf) as the upper limit and initial volume(Vi) as the lower limit

Work = p(Vf -Vi)

attempting the first question, Vi = 0.1metre cube, Vf = 0.12metre cube, p = 2bar, p(atm) = 1bar, E = U = 0.25KJ

from W = p(Vf -Vi) = 2 x 100000 ( 0.12 - 0.1) = 400N/m = 0.4KJ

To get the heat transfer, from dE = dQ - dW

Q = E + W = 0.25 + 0.4 = 0.29KJ

b) for the second question ; from Pdv = p(Vf -Vi), but the pressure here is in atmosphere

W = 100000 ( 0.12 - 0.1) = 2000KJ

6 0
3 years ago
Read 2 more answers
. True or False: It is possible with feedback control to obtain a stable closed-loop system even when the underlying open-loop s
zheka24 [161]

Answer:

True.

Explanation:

8 0
2 years ago
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