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4 years ago

A renewable item is something that is capable of being replaced naturally.

Engineering

2 answers:

rodikova [14]4 years ago

7 0

Answer:

true corect me

Explanation:

djverab [1.8K]4 years ago

6 0

The answer is False.

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Question 1 : Replacement [42 Pts] Consider the following page reference string:

MakcuM [25]

Answer:

Optimal

Time 123456789101112

RS. ecbeagdcegda

F0. eeeeeeeee e e a

F1 c c c c c c c c c c c

F2 b b b g g g g g g g

F3 a a d d d d d d

Page fault? * * * * * * *

Total page fault:7

2. LRU

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 e e e e e e e c c c c a

F1 c c c c g g g g g g g

F2 b b b b d d d d d d

F3 a a a a e e e e

Page fault? Y Y Y N Y Y Y Y Y N N Y Total page fault:9

3. LRU approximation algorithm: Second chance

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 0,e 0,e 0,e 1,e 1,e 0,e 0,e 0,e 1,e 1,e 1,e 0,e

F1 0,c 0,c 0,c 0,c 0,g 0,g 0,g 0,g 1,g 1,g 0,g

F20,b0,b0,b0,b0,d0,d0,d0,d1,d0,dF30,a0,a0,a0,c0,c0,c0,c0,a

Page fault? YYYNYYYYNNNY

Total page fault: 8

4 0

3 years ago

Read 2 more answers

A point in the x-y plane is represented by its x-coordinate and y-coordinate. Design the class Point that can store and process

Black_prince [1.1K]

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

class pointType

{

public:

pointType()

{

x=0;

y=0;

}

pointType::pointType(double x,double y)

{

this->x = x;

this->y = y;

}

void pointType::setPoint(double x,double y)

{

this->x=x;

this->y=y;

}

void pointType::print()

{

cout<<"("<<x<<","<<y<<")\n";

}

double pointType::getX()

{return x;

}

double pointType::getY()

{return y;

}

private:

double x,y;

};

int main()

{

pointType p2;

double x,y;

cout<<"Enter an x Coordinate for point ";

cin>>x;

cout<<"Enter an y Coordinate for point ";

cin>>y;

p2.setPoint(x,y);

p2.print();

system("pause");

return 0;

}

5 0

3 years ago

A supply fan is operating at 30000 cfm and 4 inch of water with an efficiency of 50%. (a) Calculate the fan power at the current

serg [7]

Answer:

The pressure and power of fan is 1.77 and 11.18 Hp respectively.

Explanation:

Given:

Discharge $Q_{1} = 30000$ cfm

Pressure difference $\Delta P = 4$ inch

Efficiency $\eta = 50\%$

(A)

From the formula of fan power,

$P _{1} = \frac{Q \Delta P}{6356 \eta}$

$P_{1} = \frac{30000 \times 4}{6356 \times 0.5}$

$P_{1} = 37.76$ Hp

(B)

Fan power and pressure is given by,

We know that pressure difference is proportional to the square of discharge.

$\frac{\Delta p_{2} }{\Delta P_{1} } = (\frac{Q_{2} }{Q_{1} } ) ^{2}$

$\Delta P_{2} = (\frac{20000}{30000} ) \times 4$

$\Delta P_{2} = 1.77$

Fan power proportional to the cube of discharge.

$\frac{P_{2} }{P^{1} } = (\frac{Q_{2} }{Q_{1} } )^{3}$

$P_{2} = \ (\frac{20000}{30000} ) ^{3} \times 37.76$

$P_{2} = 11.18$ Hp

Therefore, the pressure and power of fan is 1.77 and 11.18 Hp respectively.

5 0

3 years ago

Determine the work done by an engine shaft rotating at 2500 rpm delivering an output torque of 4.5 N.m over a period of 30 secon

balu736 [363]

Answer:

work done= 2.12 kJ

Explanation:

Given

N=2500 rpm

T=4.5 N.m

Period ,t= 30 s

$torque =\frac{power}{2\pi N}$

$power=2\pi N\times T$

P= $2\times \pi \times2500 \times 4.5$

P=70,685W

P=70.685 KW

power= $\frac{work done}{time}$

work done = power * time

= 70.685*30=2120.55J

= 2.12 kJ

7 0

4 years ago

The reason for the nature of the signal's value is: Not Linear Humans are Continuous The stock market closes once per day, and s

Serga [27]

Answer:

Explanation:

* Daily close of the stock market

The nature of the signal in value is <u>Discrete</u>, as the stock market closes once per day,and so is discrete time.
And the nature of the signal in time is continuous as the company are continuous.

8 0

3 years ago