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mylen [45]
3 years ago
9

A renewable item is something that is capable of being replaced naturally.

Engineering
2 answers:
rodikova [14]3 years ago
7 0

Answer:

true corect me

Explanation:

djverab [1.8K]3 years ago
6 0
The answer is False.
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There is a proposal in Brooklyn to construct a new mid-rise apartment building on a vacant lot at the intersection of Avenue A a
Soloha48 [4]

Answer:

a. Park should be adjacent to 48th Street, b. Difference in noise level = 707dBa, c. Yes

Explanation:

Data given for Avenue A

Cars = 496, Medium Truck = 52, Heavy Truck = 19, Buses = 10

Data given for 48th Street

Cars = 822, Medium Truck = 22, Heavy Truck = 8, Buses = 3

Consider the PCEs to be Cars = 1, Medium Truck = 13, Heavy Truck = 47, Buses = 18

a. Noise Level = Number of vehicles x PCE

For Avenue A

Noise level = (496 x 1) + (52 x 13) + (19 x 47) + (10 x 18) = 2245dBa

For 48th Street

Noise level = (822 x 1) + (22 x 13  + (8 x 47) + (3 x 18) = 1538dBa

The park should adjacent to 48th street as it is quieter than Avenue A

b. Let the Setback be 50ft. We know that the reduction of noise for 100ft = 5-8 dBa, hence

For Avenue A Noise Reduction due to 50 ft = (8/100) x 50 = 4dBa

Noise at Setback distance = 2245 - 4 = 2241dBa

Considering the same setback the noise at 48th street would be = 1538 - 4 = 1534 dBa

The difference is noise level between the two sides would be = 2241 - 1534 = 707 dBa

c. Yes the developer concerns are valid because there is a clear difference in noise levels of the two sites. This can be seen even after setting the same Setback. Locating the park next to Avenue A will cause serious noise problems.

8 0
3 years ago
A pulse-jet baghouse is desired for a finished cement plant. Calculate the number of bags required to filter 500 m3/min of air w
omeli [17]

Answer:

1) <em>4.41 * 10^-4 kw </em>

<em>2) </em>2.20 * 10^-4 kw

Explanation:

Given data:

Filter = 500 m^3/min

dust velocity = 3g/m^3

bag ; length = 3 m , diameter = 0.13 m

change in pressure = 1 kPa

efficiency = 60%

<u>1) Calculate the Fan power </u>

First :

Calculate the total dust loading = 3 * 500 = 1500 g

To determine the Fan power we will apply the relation

n_{o}  = \frac{\frac{p}{eg*Q*h} }{1000}    = \frac{\frac{p}{(3*10^{-3})* 981*( 500/60) *3  } }{1000}

<em>fan power ( </em>n_{0} )<em> = 4.41 * 10^-4 kw </em>

<u>2) calculate power drawn </u>

change in P = 6 atm = 6 * 10^5 pa

efficiency compressor = 50%

hence power drawn = 4.41 * 10^-4 kw  * 50% = 2.20 * 10^-4 kw

3 0
3 years ago
प्रहार का समरूपी भिन्नार्थक शब्द अर्थ के साथ ​
Reika [66]

Answer:

uhvdiuuauivhsifuhviudshivuhrwwwwwgyuvrrrrrrvuybgdwdoushduhsfuhdsiufhduisfhsofhuaifhuadsihfuiahfuidhsfiuhdsiufhdsaigsdygfewyihfiewbvhwegfiyerrrgqewfygediyfgdsyifguysdgfyuuaegfuyaeggfuyegwfyugewafuyegwiufggeegfyusdggfsgodqwufyew98fyyy79ewyf7eywf8777etf87tewtf

Explanation:

djhidhfdiushfiudshfui

3 0
3 years ago
Does anyone know what this is​
sammy [17]

Answer:

Looks like mold that got frosted over

Explanation:

4 0
2 years ago
Read 2 more answers
Water flows through a nozzle at the end of a fire hose. If the nozzle exit velocity must be 20 m/s and the exit diameter is 40 m
lara31 [8.8K]

Answer:

minimum flow rate provided by pump is 0.02513 m^3/s

Explanation:

Given data:

Exit velocity of nozzle = 20m/s

Exit diameter = 40 mm

We know that flow rate Q is given as

Q = A \times V

where A is Area

A =\frac{\pi}{4} \times (40\times 10^{-3})^2 = 1.256\times 10^{-3} m^2

Q = 1.256\times 10^{-3} \times 20 = 0.02513 m^3/s

minimum flow rate provided by pump is 0.02513 m^3/s

5 0
3 years ago
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