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Mariulka [41]
3 years ago
6

Create a function (prob3_5) that will take inputs of vectors x and y in feet, scalar N, scalars L and W in feet and scalars T1 a

nd T2 in degrees Fahrenheit. It will output a matrix T which is the temperature of each x and y locations. T will have the number of columns equal to the number of elements in x and rows equal to the number of elements in y. Though this can be done without loops (perhaps more efficiently), your program must use a nested loop.
Engineering
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

clear, clc

prob3_5([1,2,3],[6,5,7],12,11,22,55,76)

function T=prob3_5(x,y,N,L,W,T1,T2)

w=zeros(1,length(x));

for n=1:2:N

for i=1:length(x)

w(i)=w(i)+(2/pi)*(2/n)*sin(n*pi*x(i)/L).*sinh(n*pi*y(i)/L)/sinh(n*pi*W/L);

end

end

T=(T2-T1)*w+T1;

end

Explanation:

Please input the commands into MATLAB

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Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost m
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Answer:

ordinary bulb total cost is $39.54

fluorescent bulb total cost is $13.05

amount save = 39.54 - 13.05 = $26.49

resistance = 626.1 ohm

Explanation:

in the 1st part

bulb on time = 3 year = 4380 hours

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so

cost of operation is = 100 × 4380 × \frac{0.08}{1000}

cost of operation = $35.04

so total cost will be = $4.5 + $35.04  = $39.54

and

when compare with florescent bulb

time = 3 year = 4380 h

life of bulb = 10000 h

so number of bulb required = \frac{4380}{10000}

number of bulb required = 0.43 = 1

cost of 6 bulb is = 1 × 5 = $5

so

cost of operation is = 23 × 4380 × \frac{0.08}{1000}

cost of operation = $8.05

so total cost will be = $5 + $8.05  = $13.05

in part 2nd

total amount save while compare bulb is

amount save = 39.54 - 13.05 = $26.49

and in part 3rd

resistance of bulb is

resistance = \frac{v^2}{P}

resistance = \frac{120^2}{23}

resistance = 626.1 ohm

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Answer:

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print(team_names[1])

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print(team_names[3])

Explanation:

The Python code illustrates or printed out the tuple team names at the end of a season.

The code displayed is a function that will display these teams as an output from the program.

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1. A _____ is applied to a wall or roof rafters to add strength and keep the building straight and plumb.
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Answer:

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Which option distinguishes the step in the engineering design phase described in the following scenario?
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Answer:

reasearching the problem

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EDG

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