Drawing conclusion is the correct answer.
At s.t.p, the volume of a gas =22.4dm³
Talking the problem,
At 1atm, 273K the volume =7 moles *22.4dm³/mol
At 323K, 2.90atm, volume =?
The combined gas equation
P1v1/T1=P2v2/T2
P1=1atm
P2=2.9atm
T1=273K
T2=323K
V1=156.8dm³
Therefore,
1*156.8dm³/273=2.9atm*V2/323
V2=(156.8dm³*323K)/(273K*2.9atm)
= 64dm³
Answer:
The mass of xenon in the compound is 2.950 grams
Explanation:
Step 1: Data given
Mass of XeF4 = 4.658 grams
Molar mass of XeF4 = 207.28 g/mol
Step 2: Calculate moles of XeF4
Moles XeF4 = mass XeF4 / molar mass XeF4
Moles XeF4 = 4.658 grams / 207.28 g/mol
Moles XeF4 = 0.02247 moles
Step 3: Calculate moles of xenon
XeF4 → Xe + 4F-
For 1 mol xenon tetrafluoride, we have 1 mol of xenon
For 0.02247 moles XeF4 we have 0.02247 moles Xe
Step 4: Calculate mass of xenon
Mass xenon = moles xenon * molar mass xenon
Mass xenon = 0.02247 moles * 131.29 g/mol
Mass xenon = 2.950 grams
The mass of xenon in the compound is 2.950 grams