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Setler79 [48]
3 years ago
7

If a lab requires each a lab group (3 students) to have 25 ml of a solution and it takes 15 grams of AgNO₃ cuprous nitrate, to m

ake 1 liter of solution, how many grams are needed to make enough solution?
Chemistry
1 answer:
pochemuha3 years ago
4 0

Answer:

0.375 grams are needed to make 25 mL solution.

Explanation:

Mass of AgNO_3 cuprous nitrate required to make 1 l of solution = 15 g.

1 L = 1000 mL

Mass of AgNO_3 cuprous nitrate required to make 1000 mL of solution = 15 g

Mass of AgNO_3 cuprous nitrate required to make 1 mL of solution:

=\frac{15}{1000} g

Mass of AgNO_3 cuprous nitrate required to make 25 mL of solution:

=\frac{15}{1000} \times 25 g=0.375 g

0.375 grams are needed to make 25 mL solution.

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How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 sol
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Answer:

Time take to deposit Ni is 259.02 sec.

Explanation:

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Current I = 14.9 A

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Mass of Ni = 0.94 g

First find the no. moles in Ni solution,

Moles of Ni = \frac{0.94}{58.69}

                   = 0.02 mol

From the below reaction,

  Ni^{2+}  + 2e ⇆ Ni_{(s)}

Above reaction shows "1 mol of Ni^{2+} requires 2 mol of electron to form 1 mol of Ni_{(s)} "

So for finding charge flow in this reaction we write,

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Charge flow = 3859.4 C

For finding time of reaction,

  I = \frac{q}{t}

Where q = charge flow

   t = \frac{q}{I}

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3 0
3 years ago
The normal freezing point of a certain liquid
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Answer : The molal freezing point depression constant of liquid X is, 4.12^oC/m

Explanation :  Given,

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Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of liquid X Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X = 0.4^oC

i = Van't Hoff factor = 1 (for non-electrolyte)

K_f = Molal-freezing-point-depression constant = ?

m = molality

Now put all the given values in this formula, we get

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K_f=4.12^oC/m

Therefore, the molal freezing point depression constant of liquid X is, 4.12^oC/m

3 0
3 years ago
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