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Setler79 [48]
3 years ago
7

If a lab requires each a lab group (3 students) to have 25 ml of a solution and it takes 15 grams of AgNO₃ cuprous nitrate, to m

ake 1 liter of solution, how many grams are needed to make enough solution?
Chemistry
1 answer:
pochemuha3 years ago
4 0

Answer:

0.375 grams are needed to make 25 mL solution.

Explanation:

Mass of AgNO_3 cuprous nitrate required to make 1 l of solution = 15 g.

1 L = 1000 mL

Mass of AgNO_3 cuprous nitrate required to make 1000 mL of solution = 15 g

Mass of AgNO_3 cuprous nitrate required to make 1 mL of solution:

=\frac{15}{1000} g

Mass of AgNO_3 cuprous nitrate required to make 25 mL of solution:

=\frac{15}{1000} \times 25 g=0.375 g

0.375 grams are needed to make 25 mL solution.

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That statement is true

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3 years ago
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Which of the following explanations accounts for the fact that the ion-solvent interaction is greater for Li than for K
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Li+ has a smaller ionic radius than K+

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In the case of ion-solvent interactions, the state in which the interac-tions exist is an obvious one; it is the situation in which ions are inside the solvent.

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6 0
2 years ago
Consider the following unbalanced redox reaction:
Olegator [25]
Mn04 is being reduced
5 0
3 years ago
Mass=1.01 kg; volume =1000cm3
guajiro [1.7K]

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7 0
3 years ago
Molarity of a salt water solution of "0.47" moles of NaCl dissolved in a volume of 0.25L
asambeis [7]

Answer:

1.88 M

Explanation:

The following data were obtained from the question:

Mole of NaCl = 0.47 mole

Volume of solution = 0.25L

Molarity =?

Molarity is defined as the mole of solute per unit litre of the solution. It can represented mathematically as:

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Using the above formula, the molarity of the salt water solution can be obtained as follow:

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5 0
3 years ago
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