Answer:
NaOH and HCl
Explanation:
The reaction of sodium hydroxide, NaOH, with hydrochloric acid, HCl, produces NaCl and water.
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Answer:
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Answer:
Take 3 mL of the 5 M NaCl solution, 10 mL of the 10% glucose solution, and add water for a final volume of 100 mL.
Explanation:
- In order to calculate the required volume of the 5 M NaCl solution, we calculated the moles contained in a 100 mL solution that has a concentration of 150 mM:
0.1 L * 0.150 M = 0.015 moles of NaCl
With those moles we can calculated the required volume, using the concentration of the stock solution:
0.015 mol / 5 M = 0.003 L = 3 mL.
- To make a solution that has a 1 % concentration of glucose, from a 10 % glucose solution, is the same as to make it ten times less concentrated. Thus, with a final volume of 100 mL, you would need to take 10 mL of the 10% glucose solution, because 100mL * 10/100 = 10.
So in order to prepare the solution, you would need to take 3 mL of the 5 M NaCl solution, 10 mL of the 10% glucose solution, and add water for a final volume of 100 mL.
