Answer: I think probaly wrong so probaly dont
listen to me
Explanation:
Answer: D.
Explanation: D. Acetone, Acetone may be rinsed over materials to wash off the explosive residue.
Hope this helps :)
Answer:
30.0g CaCl2
Explanation:
20.0g Ca(OH)2=0.270mol
(0.270mol)(111.0g/mol)=30.0g CaCl2
Answer:
Mass of Rb-87 is 86.913 amu.
Explanation:
Given data:
Average mass of rubidium = 85.4678 amu
Mass of Rb-85 = 84.9117
Ratio of 85Rb/87Rb in natural rubidium = 2.591
Mass of Rb = ?
Solution:
The ration of both isotope is 2.591 to 1. Which means that for 2.591 atoms of Rb-85 there is one Rb-87.
For 100% naturally occurring Rb = 2.591 + 1 = 3.591
% abundance of Rb-85 = 2.591/ 3.591 = 0.722
% abundance of Rb-87 = 1 - 0.722= 0.278
84.9117 × 0.722 + X × 0.278 = 85.4678
61.306 + X × 0.278 = 85.4678
X × 0.278 = 85.4678 - 61.306
X × 0.278 = 24.1618
X = 24.1618 / 0.278
X = 86.913 amu
Hey there!
density = 2.67 g/cm³
mass = 1340 g
volume = ?
Therefore:
D = m / V
2.67 = 1340 / V
V = 1340 / 2.67
V = 501.87 cm³