Using the balanced chemical equation below. 2Al2O3 --> 4Al + 3O2 How many moles of oxygen are produced if 11.0 mol of Al are
1 answer:
Answer:
8.25 moles of oxygen will be produced.
Explanation:
Given a balanced chemical equation;
2Al₂O₃ ------> 4Al + 3O₂
from the balanced chemical equation above, 3 moles of Oxygen are produced when 4 moles of Aluminum are produced.
4 moles of Al --------> 3 moles of Oxygen
11 moles of Al --------> ?
Therefore, 8.25 moles of oxygen will be produced.
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Answer:
A) ,
,
A = 1.5×, A = 1.9×
, A=1.5×
B) 4.469
Explanation:
From Arrhenius equation
where; K = Rate of constant
A = Pre exponetial factor
= Activation Energy
R = Universal constant
T = Temperature in Kelvin
Given parameters:
taking logarithm on both sides of the equation we have;
since we have the rate of two different temperature the equation can be derived as:
= 19846.04×7.544×
= 1.497
=
= 4.469
If acetone has a density of 0.7857 the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.
Acetone is known as a chemical substance that is usually found in the environment but can also be produced artificially. Acetone is a polar organic product that interacts very well with water molecules, generating dipole-dipole relationships.It is colorless with a distinctive smell and taste, we find it in products known as <u>cleaning and personal care products</u>, but we can also use it as a solvent for substances.
Also in the environment in <u>plants, trees and in volcano emissions or in forest fires</u>, it does not become <em>toxic</em> in low doses but if it is exposed to an individual in high doses it can become <em>fatal</em>.
In the statement we can find that acetone has a density of 0.7857 .
Therefore, we can confirm that if acetone has a density of 0.7857 the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.
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