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Norma-Jean [14]
3 years ago
6

Using the balanced chemical equation below. 2Al2O3 --> 4Al + 3O2 How many moles of oxygen are produced if 11.0 mol of Al are

produced?
Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

8.25 moles of oxygen will be produced.

Explanation:

Given a balanced chemical equation;

2Al₂O₃ ------> 4Al + 3O₂

from the balanced chemical equation above, 3 moles of Oxygen are produced when 4 moles of Aluminum are produced.

4 moles of Al --------> 3 moles of Oxygen

11 moles of Al --------> ?

= \frac{(3 \ moles \ of \ O_2) \ \times \ (11 \ moles \ of \ Al)}{4 \ moles \ of \ Al} = 8.25 \ moles \ of \ O_2 \\\\

Therefore, 8.25 moles of oxygen will be produced.

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A neutral atom has 1 valence electron and its atomic mass is 39. How many
uranmaximum [27]

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Explanation:

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3 years ago
___ may be rinsed over materials to was off explosive residue. A) water B) bleach C) acid D) acetone
Sergio [31]

Answer: D.

Explanation: D. Acetone, Acetone may be rinsed over materials to wash off the explosive residue.

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4 0
3 years ago
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How many grams of calcium chloride are required to make 20 grams of calcium hydroxide? CaCl2 + 2 NaOH → Ca(OH)2 + 2 NaCl
KatRina [158]

Answer:

30.0g CaCl2

Explanation:

20.0g Ca(OH)2=0.270mol

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6 0
3 years ago
natural rubidium has the average mass of 85.4678 and is composed of isotopes 85 Rb(mass = 84.9117) and 87 Rb. The ratio of atoms
mote1985 [20]

Answer:

Mass of Rb-87 is 86.913 amu.

Explanation:

Given data:

Average mass of rubidium = 85.4678 amu

Mass of Rb-85 = 84.9117

Ratio of 85Rb/87Rb in natural rubidium = 2.591

Mass of Rb = ?

Solution:

The ration of both isotope is 2.591 to 1. Which means that for 2.591 atoms of Rb-85 there is one Rb-87.

For 100% naturally occurring Rb = 2.591 + 1 = 3.591

% abundance of Rb-85 = 2.591/ 3.591 = 0.722

% abundance of Rb-87 = 1 - 0.722= 0.278

84.9117 × 0.722 + X × 0.278 = 85.4678

61.306 + X × 0.278 = 85.4678

X × 0.278 = 85.4678 - 61.306

X × 0.278 = 24.1618

X =  24.1618 / 0.278

X = 86.913 amu

8 0
3 years ago
A certain liquid has a density of 2.67 g/ cm3. what is the volume occupied by 1340 g of this liquid?
morpeh [17]
Hey there!

density = 2.67 g/cm³

mass = 1340 g

volume = ?

Therefore:

D = m / V

2.67 = 1340 / V

V = 1340 / 2.67

V = 501.87 cm³
7 0
3 years ago
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