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____ [38]
3 years ago
13

An object's mechanical energy is the sum of its

Chemistry
1 answer:
n200080 [17]3 years ago
3 0
Potential energy or kinetic energy.
You might be interested in
How many watts would equal 137 kilowatts?
natka813 [3]

Answer:

137,000 watts

Explanation:

1 kilowatt = 1000 watts

137 kilowatts = 1000 × 137 watts

= 137,000 watt

5 0
3 years ago
Read 2 more answers
a balloon filled with 750.0 ml of helium at a temperature of 25 degrees celsius and an atmosphere pressure of 745 mm Hg. What vo
Softa [21]

Answer:

V₂ = 0.98 L

Explanation:

Given data:

Initial volume = 750 mL  =0.75 L

Initial pressure = 745 mmHg (745/760 =0.98 atm)

Initial temperature = 25 °C (25 +273 = 298 K)

Final temperature = -35°C (-35+273 = 238 K)

Final volume = ?

Final pressure = 0.60 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂/T₁ P₂

V₂ = 0.98 atm × 0.75 L × 238 K / 298 K × 0.60 atm

V₂ = 174.93 atm .L. K / 178.8  K.atm

V₂ = 0.98 L

4 0
3 years ago
A 18.08-g sample of the ionic compound , where is the anion of a weak acid, was dissolved in enough water to make 116.0 mL of so
Oksi-84 [34.3K]

Answer:

a) 129.14 g/mol

b) 8.87

Explanation:

Given that:

mass of the ionic compound [NaA] = 18.08 g

Volume of water = 116.0 mL = 0.116 L

Let the mole of the acid HCl = 0.140 M

Volume of the acid = 500.0 mL = 0.500 L

pH = 4.63

V_{equivalence}_{acid} = 1.00 L

Equation for the reaction can be represented as:

NaA_{(aq)} + HCl_{(aq)} -----> HA_{(aq)} + NaCl_{(aq)

From above; 1 mole of an ionic compound reacts with 1 mole of an acid to reach equivalence point = 0.140 M × 1.00 L

= 0.140 mol

Thus, 0.140 mol of HCl neutralize 0.140 mol of ionic compound at equilibrium

Thus, the molar mass of the sample = \frac{18.08g}{0.140 mole}

= 129.14 g/mol

b) since pH = pKa

Then pKa of HA = 4.63

Ka = 10^{-4.63]

= 2.3*10^{-5}

[A^-]equ = \frac{0.140M*1.00L}{1.00L+0.116L}

= \frac{0.140 mol}{1.116 L}

= 0.1255 M

K_a of HA = 2.3*10^{-5}

K_b = \frac{1.0*10^{-14}}{2.3*10^{-5}}

= 4.35*10^{-10}

                     A_{(aq)}     +     H_2O_{(l)}         \rightleftharpoons     HA_{(aq)}     +     OH^-_{(aq)}

Initial        0.1255                                            0                    0

Change     - x                                                  +  x                 + x

Equilibrium   0.1255 - x                                   x                    x

K_b = \frac{[HA][OH^-]}{[A^-]}

4.35*10^{-10} = \frac{[x][x]}{[0.1255-x]}

As K_b is very small, (o.1255 - x) = 0.1255

x = \sqrt{0.1255*4.35*10^{-10}}

[OH⁻] = x = 7.4 *10^{-6}

But pOH = - log [OH⁻]

= - log [7.4*10^{-6}]

= 5.13

pH = 14.00 = 5.13

pH = 8.87

6 0
3 years ago
Which of the following will decrease the pressure of a gas in a closed container?
ch4aika [34]
A
Now gimmie brainliest
8 0
3 years ago
What is the answer please and why is this answer
Korolek [52]
C. Between ages 2 and 3
3 0
3 years ago
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