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Mkey [24]
3 years ago
7

. A 5.00 – g sample of lead is bluish-white in color and is very soft and malleable. It has a melting point of 327.4°C and a boi

ling point of 1620°C. At 20°C the density of the lead sample is 11.35 g –cm-3. Which property of the sample is an extensive property?
Chemistry
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

The mass of the lead

Explanation:

The 5g mass of the lead is an extensive property.

An extensive property is a physical property of matter which depends on the amount of matter that is present there in. Mass, volume e.t.c are all extensive properties. The more the quantity of the lead, the more its mass and the volume it occupies.

Melting point, boiling point, density are all intensive propeties. These properties do not rely on the amount of matter present. Any amount of lead will have the same density.

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(c) He, Na, Mg (increasing order of melting point).​
blondinia [14]

Answer:

Helium has melting point of - 272.2°C or - 458°F

Sodium (Na) = 650°C. or 208°C

Magnesium (Mg) = 97.79°C. Or 1202°F

Explanation:

4 0
3 years ago
HELP ASAP MY LESSON IS BEING TIMED!!!
77julia77 [94]

Answer:

1. Newton's third law of motion

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3. Action

7 0
3 years ago
Read 2 more answers
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Rina8888 [55]

Answer:

C. Particle size

Explanation:

The sand, which has smaller particles, will go through the sieve, while the rice (with a larger particle size) will not

4 0
2 years ago
Is the number of total molecules on the left side of a balanced equation always equal to the number of total molecules on the ri
Nadya [2.5K]

Answer:

No

Explanation:

No, but the total mass of reactants must equal the total mass of products to be a balanced equation.

Example: Consider the following reaction ...

3H₂ + N₂ => 2NH₃ and 'amu' is atomic mass units (formula weights from periodic table)

In terms of molecules, there are 4 molecules on the left (3 molecular hydrogens (H₂) and 1 molecular nitrogen (N₂) and 2 molecules of ammonia on the right side of equation arrow. ∑reactant molecules ≠ ∑product molecules.

In terms of mass of reactants & mass of products, the 3H₂ + N₂ => 6amu + 28amu = 34amu & mass of products (2NH₃) => 2(14amu) + 6(1amu) = 34amu for sum of product masses.

∑mass reactants = ∑mass products <=> 34amu = 34amu.

The expression '∑mass reactants = ∑mass products' as applied to chemical equations is generally known as 'The Law of Mass Balance'.

3 0
3 years ago
Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each
Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0
3 years ago
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