Question

If a resistor of 6 kohms is rated at a maximum power dissipation of 0.5 watts, what is the maximum current it can safely handle without damage?

Answer 1

Answer : The maximum current will be, $9.13\times 10^{-3}A$

Explanation :

The relationship between power, resistance and current is:

$P=I^2\times R$

where,

P = power = 0.5 watts

I = current = ?

R = resistance = 6 kohms = 6000 ohms

Now put all the given values in the above formula, we get:

$0.5=I^2\times 6000$

$I=9.13\times 10^{-3}A$

Thus, the maximum current will be, $9.13\times 10^{-3}A$