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Contact [7]
3 years ago
10

Calculate the current in a circuit when the voltage of the circuit is 5 V and the circuit has a total resistance of 5 Ω.

Physics
1 answer:
seropon [69]3 years ago
8 0

the answer is 1a as rearrange gives I = v divided by r

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Which piece of evidence did Alfred Wegener use to develop the theory of continental drift?
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The right answer for the question that is being asked and shown above is that: "A.tectonic activity concentrated in certain areas." A piece of evidence did Alfred Wegener use to develop the theory of continental drift is that <span>A.tectonic activity concentrated in certain areas</span>
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3 years ago
Explain why the speed of light is lower than 3.0 × 108 m/s as it goes through different media.
alexandr1967 [171]

Answer:

air or vacuum is the least refractive index medium of most rare medium

all other medium has more value of refractive index and hence the speed will be less than the speed of the air

Explanation:

As we know that speed of light in any medium and speed of light in air is related to each other by the equation

v = \frac{c}{\mu}

here we know that

c = 3 \times 10^8 m/s

[tex]\mu [tex] = refractive index of the medium

so we know that air or vacuum is the least refractive index medium of most rare medium

all other medium has more value of refractive index and hence the speed will be less than the speed of the air

4 0
3 years ago
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A 60.watt light bulb runs for 5.0 seconds. How much energy does it use?
VikaD [51]

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"60 watts" means "60 Joules per second"

(60 joules per second) x (5 seconds) = <em>300 Joules of energy</em>

5 0
4 years ago
Explain why the duster accelerates different rates when different surfaces are in contact with the track
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Because on different surfaces there's more/less friction. Smooth surfaces will allow the duster to accelerate while rough surfaces will decrease the acceleration.

8 0
3 years ago
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Ch 31 HW Problem 31.63 10 of 15 Constants In an L-R-C series circuit, the source has a voltage amplitude of 116 V , R = 77.0 Ω ,
Degger [83]

Answer:

a. I = 0.76 A

b. Z = 150.74

c. RL₁ = 34.41  ,  RL₂ = 602.58

d. RL₂ = 602.58

Explanation:

V₁ = 116 V , R₁ = 77.0 Ω , Vc = 364 V ,  Rc = 473 Ω

a.

Using law of Ohm

V = I * R

I = Vc / Rc =  364 V / 473 Ω

I = 0.76 A

b.

The impedance of the circuit in this case the resistance, capacitance and inductor

V = I * Z

Z = V / I

Z = 116 v / 0.76 A

Z = 150.74

c.

The reactance of the inductor can be find using

Z² = R² + (RL² - Rc²)

Solve to RL'

RL = Rc (+ / -) √ ( Z² - R²)

RL = 473 (+ / -)  √ 150.74² 77.0²

RL = 473 (+ / -)  (129.58)

RL₁ = 34.41  ,  RL₂ = 602.58

d.

The higher value have the less angular frequency  

RL₂ = 602.58

ω = 1 / √L*C

ω = 1 / √ 602.58 * 473

f = 285.02 Hz

6 0
4 years ago
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