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Ira Lisetskai [31]
3 years ago
15

3. The pressure at the bottom of the ocean is great enough to crush submarines with steel walls that are 10 centimeters thick. S

uppose a submarine is at a depth of 1,000 meters. The weight of water above each square meter of the submarine is 9,800,000 newtons.
Physics
2 answers:
Arada [10]3 years ago
8 0

Answer:

answer one

Explanation:

Elden [556K]3 years ago
3 0

Answer:

just awnsered this one your awnser is the the second option

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A force of 6600 N is exerted on a piston that has an area of 0.010 m2
sveticcg [70]

Answer:

Choice A: approximately 0.015\; \rm m^2, assuming that the two pistons are connected via some confined liquid to form a simple machine.

Explanation:

Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:

\displaystyle P_1 = \frac{F_1}{A_1} = \frac{6.600\times 10^3\; \rm N}{1.0\times 10^{-2}\; \rm m^{2}} = 6.6\times 10^{5}\; \rm N \cdot m^{-2}.

By Pascal's Principle, because the first piston exerted a pressure of 6.6\times 10^{5}\; \rm N \cdot m^{-2} on the liquid, the liquid will now exert the same amount of pressure on the walls of the container.

Assume that the second piston is part of that wall. The pressure on the second piston will also be 6.6\times 10^{5}\; \rm N \cdot m^{-2}. In other words:

P_2 = P_1 = 6.6\times 10^{5}\; \rm N \cdot m^{-2}.

To achieve a force of 9.900 \times 10^3\; \rm N, the surface area of the second piston should be:

\displaystyle A_2 = \frac{F_2}{P_2} = \frac{9.900\times 10^{3}\; \rm N}{6.6\times 10^5\; \rm N \cdot m^{-2}} \approx 0.015\; \rm m^{2}.

4 0
3 years ago
Name the type of particle formed by covalent bonds
jasenka [17]
Molecules and polyatomic ions are formed by covalent bonds.
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3 years ago
The direction of the acceleration of an object on a(n) _______________________ path is toward the _______________________ of the
aleksandrvk [35]

Answer:

circular...center

Explanation:

Physics

8 0
3 years ago
A parked car's horn (belonging to a musician) emits a concert A of frequency 440 on a day when the speed of sound is 342 m/s. Yo
julsineya [31]

Answer:

19.08 m/s

Explanation:

f = actual frequency emitted by the parked car's horn = 440 Hz

V = speed of sound = 342 m/s

f' = frequency of the horn observed by you = 466 Hz

v = speed of your car moving towards the parked car = ?

frequency of the horn observed by you is given as

f' = \frac{Vf}{V - v}

466 = \frac{(342)(440)}{342 - v}

v = 19.08 m/s

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Inessa05 [86]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Change in market price is m<span>ovement along the demand curve. </span>

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