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Anna [14]
3 years ago
8

How much money do you guys make off of this lame website?

Chemistry
2 answers:
Law Incorporation [45]3 years ago
8 0

enough to pay bills :)

MrRissso [65]3 years ago
7 0

Answer:

so far from what i've seen its been 80 mil

Explanation:

the power of GoogIe

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Which of the following is a change from a less condensed to a more condensed state of matter?. . Boiling. . Evaporating. . Conde
Masja [62]
Condensation, among the following options given in the question is a change from a less condensed to a more condensed state of matter. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope the answer comes to your help.
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3 years ago
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How many hydrogen grams can be obtained if
kipiarov [429]

hi im breanna

Answer:

The mole is simply a very large number that is used by chemists as a unit of measurement.

Explanation:

The mole is simply a very large number,  

6.022

×

10

23

, that has a special property. If I have  

6.022

×

10

23

hydrogen atoms, I have a mass of 1 gram of hydrogen atoms . If I have  

6.022

×

10

23

 

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6.022

×

10

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C

atoms, I have (approximately!) 12 grams.

The mole is thus the link between the micro world of atoms and molecules, and the macro world of grams and litres, the which we can easily measure by mass or volume. The masses for a mole of each element are given on the periodic table as the atomic weight. So, if have 12 g of  

C

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O

2

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5 0
3 years ago
How many atoms are in 0.625 moles of ge (atomic mass = 72.59 amu)?
lord [1]
0.625 moles of ge X 6.02x10^23 atoms/ 1 mol of ge equal to 3.76x10^23 atoms of ge, just times with Avogadro.
8 0
3 years ago
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The volume of a gas with an initial pressure of 380 mmHg increases from 5.0 L to 8.0 L. What is the final pressure of the gas, i
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I hope this helped out! Have a nice day :)
6 0
3 years ago
2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??
Zepler [3.9K]

Answer:

d=1.78\times 10^{-7}\ Dg/\mu m^3

Explanation:

Given,

The density of Helium is 1.78\times 10^4\ g/cm^3

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3

So, the density of Helium is equal to 1.78\times 10^{-7}\ Dg/\mu m^3.

4 0
3 years ago
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