Answer:
60 moles of NaF
Explanation:
The balanced equation for the reaction is given below:
Al(NO3)3 + 3NaF —> 3NaNO3 + AlF3
From the balanced equation above,
3 moles of NaF reacted to produce 1 mole of AlF3.
Therefore, Xmol of NaF will react to produce 20 moles of AlF3 i.e
Xmol of NaF = 3 x 20
Xmol of NaF = 60 moles
Therefore, 60 moles of NaF are required to produce 20 moles of AlF3.
Then, at a critical point during interphase (called the S phase), the cell duplicates its chromosomes and ensures its systems are ready for cell division. If all conditions are ideal, the cell is now ready to move into the first phase of mitosis.
There are two sites on the antibody molecule that have a potential to bind to a non-self molecule. The Fab of an antibody is the region of the antibody that binds to an antigen. It consist of one constant and one variable domain from each heavy and light chain of the antibody. During immune reaction, an antigen-antibody reaction occurs between the antibodies made by the B cells and the antigens.
Luster deals with the way light reflects off a mineral
