The change in surface area of Gaussian surface with radius (r) is 8πr.
<h3>
Electric field from Coulomb's law</h3>
The electric field experienced by a charge is calculated as follows;
where;
- E is the electric field
- Q is the charge
- r is the radius
The electric field reduces by a factor of 
<h3>Surface area of a Gaussian surface;</h3>
The surface area of a sphere is given as;
<h3>Change in area with r</h3>
Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.
Learn more about area of Gaussian surfaces here: brainly.com/question/17060446
D. 558 km/h because if you divide 1,395 by 2.5 you’ll get the answer and I know this is correct because the keyword for me to divide is average.
Your stomach. afterwards it is dissolved by the stomach acid and the nutrients travel to your cells
I think it is chlorine
protons =17
z= 17
neutron=18
When saturated air is cooled, it simply reaches its dew point. Dew point is simply the temperature at which dew begins to form.
Dew point of saturated air is already pre-determined by how much water vapor the air contains. A state of saturation exists when the air is holding the maximum amount of water vapor possible at the existing temperature and pressure. The higher the dew point, the higher the moisture content of the air. Cooling does not change the dew point of saturated air, rather its the level of saturation.
So if the air has more moisture, dew will form at a higher temperature and vice versa, but dew point is NEVER EVER GREATER than the air temperature.
