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Igoryamba
3 years ago
5

The tendency of molecules to move toward areas of low concentration is called______.

Chemistry
1 answer:
Tems11 [23]3 years ago
6 0
I think the answer is D. Diffusion
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The atomic masses of any two elements contain the same number of
den301095 [7]

Answer:

They contain of atoms

Explanation:

That's because atomic weights or masses of each atom of each element are proportional to each other, the same number of atoms of each element will give masses that are also proportional to each other. If you start with 20 oxygen atoms, you will need 40 hydrogen atoms to make the water and you will get 20 molecules of water.

8 0
3 years ago
What would happen if you used a warm washcloth if you had a fever.
aivan3 [116]
You will feel way better because in our class we learned that lukewarm baths are good for fevers and warm washcloths :)
3 0
3 years ago
Nonmetals are defined as elements that generally cannot conduct:.
polet [3.4K]

Answer:

Electricity

Explanation:

Nonmetals are defined as elements that generally cannot conduct electricity

3 0
2 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.314 kg of water?
Mariulka [41]

Answer:

g NaCl = 424.623 g

Explanation:

<em>C</em> NaCl = 3.140 m = 3.140 mol NaCl / Kg solvent

∴ solvent: H2O

∴ mass H2O = 2.314 Kg

mol NaCl:

⇒ mol NaCl = (3.140 mol NaCl/Kg H2O)×(2.314 Kg H2O) = 7.266 mol NaCl

∴ mm NaCl = 58.44 g/mol

⇒ g NaCl = (7.266 mol NaCl)×(58.44 g/mol) = 424.623 g NaCl

5 0
3 years ago
The molar solubility of pbi2 is 1.5 103 m.
Vsevolod [243]

Answer: -

Concentration of PbI₂ = 1.5 x 10⁻³ M

PbI₂ dissociates in water as

PbI₂ ⇄ Pb²⁺ + 2 I⁻

So PbI₂ releases two times the amount of I⁻ as it's own concentration when saturated.

Thus the molar concentration of iodide ion in a saturated PbI₂ solution = [ I⁻] =

= 1.5 x 10⁻³ x 2 M

= 3 x 10⁻³ M

PbI₂ releases the same amount of Pb²⁺ as it's own concentration when saturated.

[Pb²⁺] = 1.5 x 10⁻³ M

So solubility product for PbI₂

Ksp = [Pb²⁺] x [ I⁻]²

=1.5 x 10⁻³ x (3 x 10⁻³)²

= 4.5 x 10⁻⁹

8 0
3 years ago
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