To answer this question, you need to know <span>Graham's Law of Effusion/Diffusion formula. In this formula, the rate of diffusion/effusion would be influenced by the mass. As the molecule has bigger mass, the rate should be slower because it will be harder to pass the membrane. The calculation should be:</span>
<span>Rate 1 / Rate 2 = √[M2/M1]
</span>4.11/1= √[M2/2]
M2=33.78 g/mol
By 'waves' do you mean sound waves? If so sound waves need to travel through things like solids, liquids and yup <u>gases. </u>When the waves travel they are vibrating the molecules in the matter. By doing this he molecules in solids are packed very tightly.
Answer:True
Explanation: An anion has a larger radius than a neutral atom because it gains valence electrons. There are added electron/electron repulsions in the valence shell that expand the size of the electron cloud, which results in a larger radius for the anion.
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Answer:
Explanation:
From the given information:
TO start with the molarity of the solution:

= 0.601 mol/kg
= 0.601 m
At the freezing point, the depression of the solution is 

Using the depression in freezing point, the molar depression constant of the solvent 


The freezing point of the solution 

The molality of the solution is:

Molar depression constant of solvent X, 
Hence, using the elevation in boiling point;
the Vant'Hoff factor 


Answer:
The boiling point is 308.27 K (35.27°C)
Explanation:
The chemical reaction for the boiling of titanium tetrachloride is shown below:
Ti
⇒ Ti
ΔH°
(Ti
) = -804.2 kJ/mol
ΔH°
(Ti
) = -763.2 kJ/mol
Therefore,
ΔH°
= ΔH°
(Ti
) - ΔH°
(Ti
) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol
Similarly,
s°(Ti
) = 221.9 J/(mol*K)
s°(Ti
) = 354.9 J/(mol*K)
Therefore,
s° = s° (Ti
) - s°(Ti
) = 354.9 - 221.9 = 133 J/(mol*K)
Thus, T = ΔH°
/s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C
Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.