I think the correct answer would be the third option. The reason I2 has a higher melting point than F2 is because I2 possesses a more polarizable electron cloud. I2 contains more electrons than F2 which would result to a stronger intermolecular forces. Having stronger intermoleculer forces would mean more energy is needed to break the bonds so a higher melting point would be observed.
Temperature change, colour change, releasing gas, bubbles and change in odor
Answer: balanced chemical equation: ![Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaNO_3(aq)](https://tex.z-dn.net/?f=Ba%28NO_3%29_2%28aq%29%2BNa_2SO_4%28aq%29%5Crightarrow%20BaSO_4%28s%29%2B2NaNO_3%28aq%29)
Net ionic equation :
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
The balanced chemical equation is:
![Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaNO_3(aq)](https://tex.z-dn.net/?f=Ba%28NO_3%29_2%28aq%29%2BNa_2SO_4%28aq%29%5Crightarrow%20BaSO_4%28s%29%2B2NaNO_3%28aq%29)
Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.
The ions which are present on both the sides of the equation are sodium and nitrate ions and hence are not involved in net ionic equation.
Hence, the net ionic equation is
The color of light that will be diffracted at a greater angle from a diffracting grating is THE YELLOW COLOR.
This is because, the degree of diffraction depend on the wavelength of light and light color with shorter wavelength are diffracted at a larger angle than those with longer wavelengths. The wavelength of the yellow color is much more smaller than that of the red color.
Answer:
We need 0.375 mol of CH3OH to prepare the solution
Explanation:
For the problem they give us the following data:
Solution concentration 0,75 M
Mass of Solvent is 0,5Kg
knowing that the density of water is 1g / mL, we find the volume of water:
![d = \frac{g}{mL} \\\\ V= \frac{g}{d} = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bg%7D%7BmL%7D%20%5C%5C%5C%5C%20V%3D%20%5Cfrac%7Bg%7D%7Bd%7D%20%20%3D%20%5Cfrac%7B500g%7D%7B1%20%5Cfrac%7Bg%7D%7BmL%7D%20%7D%20%3D%20500mL%20%3D%200%2C5%20L)
Now, find moles of
are needed using the molarity equation:
therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH, resulting in a concentration of 0,75M