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Troyanec [42]
3 years ago
14

Type of change that doesn't involve the formation of new kind of matter

Chemistry
2 answers:
Artyom0805 [142]3 years ago
7 0
A physical change, ie tearing a piece of paper in half.
vovangra [49]3 years ago
3 0
A physical change, it's like breaking your pencil
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A sample of solid NH 4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (at
UNO [17]

Answer:

The answer to the question is

The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.

Explanation:

To solve the question, we write out the chemical equation as follows

NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)

From the above equation, it is observed that only the gaseous products contribute to the partial pressure

Kp =PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases

However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S

Then PNH₃  = √(0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.

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3 years ago
In this reaction which substance behaves as the oxidizing agent pb
VashaNatasha [74]
Check the attached file for the answer.

6 0
3 years ago
Imagine that you're able to fully dissolve a powdered substance in water. what can be said about this creation
ehidna [41]
<span>the water is the solvent, and the powder is the solute. This is also a solution altogether. </span>
8 0
3 years ago
During surgery, a patient receives 3.5 pt of plasma. How many milliliters of plasma were given?
Readme [11.4K]

Answer:

1656.116

Explanation:

473.176 is how many millimetres equals a pint and you would multiply that by 3.5

4 0
3 years ago
Deep sea divers use a mixture of helium and oxygen to breathe. Assume that a diver is going to a depth of 150 feet where the tot
Svetlanka [38]

Answer:

4.525% is the percentage by volume of oxygen in the gas mixture.

Explanation:

Total pressure of the mixture = p = 4.42 atm

Partial pressure of the oxygen = p_1=0.20 atm

Partial pressure of the helium = p_2

p_1=p\times \chi_1 (Dalton law of partial pressure)

0.20 atm=4.42 atm\times \chi_1

\chi_1=\frac{0.20 atm}{4.42 atm}=0.04525

\chi_2=1-\chi_1=1-0.04525=0.95475

chi_1+chi_2=1

n_1=0.04525 mol,n_2=0.95475 mol

According Avogadro law:

Moles\propto Volume (At temperature and pressure)

Volume occupied by oxygen gas  =V_1

Total moles of gases = n = 1 mol

Total Volume of the gases = V

\frac{n_1}{V_1}=\frac{n}{V}

\frac{V_1}{V}=\frac{n_1}{n}=\frac{0.04525 mol}{1 mol}

Percent by volume of oxygen in the gas mixture:

\frac{V_1}{V}\times 100=\frac{0.04525 mol}{1 mol}\times 100=4.525\%

6 0
4 years ago
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