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Troyanec [42]
3 years ago
14

Type of change that doesn't involve the formation of new kind of matter

Chemistry
2 answers:
Artyom0805 [142]3 years ago
7 0
A physical change, ie tearing a piece of paper in half.
vovangra [49]3 years ago
3 0
A physical change, it's like breaking your pencil
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a block of wood has a density of 0.95 g/cm3. will it float or sink when placed on a liquid with a density of 0.88 g/mL? explain
vesna_86 [32]
Since 1mL=1cm^3 the wood would sink due to it being more dense. I.e. 0.95>0.88
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3 years ago
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What evidence supports the law of conservation of energy?
Travka [436]

Answer:

light energy is converted to chemical energy during photosynthesis.

Explanation:

Law of conservation of energy says: Energy can neither be created nor destroyed-only converted from one form of energy to another.

3 0
2 years ago
Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)
Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

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3 years ago
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The answer would be
1.553676 \times  {10}^{24}
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