You need 3/4 yard of ribbon for one gift box. You have 3 yards of ribbon. How many gift boxes do you have ribbon for

Mathematics

1 answer:

Kazeer [188]3 years ago

7 0

Answer:

Step-by-step explanation:

You take 3/4 + 3/4 and add it. That equals 1.5, so you take 3/4+ 3/4 again and you get 1.5 . So, 1.5+1.5 is 3. So that's how you get your total of 4 boxes.

You might be interested in

Find the product.

Nimfa-mama [501]

Answer:

I dont know what letter but its 12i^2+i+6

Step-by-step explanation:

cross multiply

8 0

3 years ago

6. a. Sixty students in a class took an examination in Physics and Mathematics. If 17 of them passed Physics only, 25 passed in

Ivahew [28]

Let $C$ be the set of all students in the classroom.

Let $P$ and $M$ be the sets of students that pass physics and math, respectively.

We're given

$n(C) = 60$

$n(P \cap M') = 17$

$n(P \cap M) = 25$

$n((P \cup M)') = n(P' \cap M') = 9$

i. We can split up $P$ into subsets of students that pass both physics and math $(P\cap M)$ and those that pass only physics $(P\cap M')$ . These sets are disjoint, so