Most of the problem depends on which object you observe. For the speed, take the absolute value of the derivative of the polynomial interpolation of position verses time.
Answer:
a) 51.8 m, b) 27.4 m/s, c) 142 m
Explanation:
Given:
v₀ = 42.0 m/s
θ = 60.0°
t = 5.50 s
Find:
h, v, and H
a) y = y₀ + v₀ᵧ t + ½ gt²
0 = h + (42.0 sin 60.0) (5.50) + ½ (-9.8) (5.50)²
h = 51.8 m
b) vᵧ = gt + v₀ᵧ
vᵧ = (-9.8)(5.5) + (42.0 sin 60.0)
vᵧ = -17.5 m/s
vₓ = 42.0 cos 60.0
vₓ = 21.0 m/s
v² = vₓ² + vᵧ²
v = 27.4 m/s
c) vᵧ² = v₀ᵧ² + 2g(y - y₀)
0² = (42.0)² + 2(-9.8)(H - 51.8)
H = 142 m
Answer:
Option (b) will be correct answer for accelerating the car
Explanation:
For accelerating the car we have to speed up the car
In option (b) it is given that stepping on the gas pedal to speed up the car so it is correct answer
In option (c) it is given that pressing the pedal to slow down the car it is a case of deceleration so it is a incorrect statement.
In option (d) it is given that speed is constant at curved path so acceleration will be zero because if there is no change in velocity then acceleration will be zero
