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kow [346]
3 years ago
9

What is the difference between habitats and niches?

Physics
2 answers:
jeyben [28]3 years ago
5 0
Habitats is a place were someone or something lives, and idk what a ninch is 

Gnom [1K]3 years ago
3 0

Though the two exist within each other, they are two separate concepts and have different roles. A habitat is where a living organism resides. Many other organisms can also reside in the same habitat as others. To put it in simpler terms, a habitat is like a living organisms home, or more closely like an apartment building, each organism having their own home or place, but all in the same place. On the other hand, a niche is an organism's role in the habitat. All the organisms in the habitat all have a separate role from one another, but all work in harmony to keep the habitat running. A niche is like the organisms going out to work, to come back and pay for the apartment, with all the added income, it keeps the building running.

Felt like this needed a better answer. Got me 100% on endgenuity.

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A)Watt (W) is a derived unit.
Aleks04 [339]

Answer:

a) Watt is a derived unit because it's not a “base unit.”

b) The atomic clock is suitable for measuring time because natural atomic oscillations happen at a higher frequency and as a result they are more stable.

c) There is fluctuation in time measured by a pendulum clock because the pendulum rod changes in length slightly with changes in temperature, causing changes in the rate of the clock. An increase in temperature causes the rod to expand, making the pendulum longer, so its period increases and the clock loses time.

D) The weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.

e) The weight of an object on the moon is about one-sixth the weight it would have on the earth because the moon's gravitation force is determined by the mass and the size of the moon. Hence, the weight of an object on the moon is 1/6th its weight on the earth.

4 0
3 years ago
A stuntman of mass 55 kg is to be launched horizontally out of a spring-
zepelin [54]

Answer:20

Explanation: i konw this stuff

6 0
3 years ago
A ball of mass 4.5 kg moving with speed of 2.2 m/s in the +x-direction hits a wall and bounces back with the same speed in the x
Levart [38]

Answer:

The change of the momentum of the ball is -19.8\, \frac{mkg}{s}

Explanation:

We should find \varDelta\overrightarrow{p}=\overrightarrow{p_{f}}-\overrightarrow{p_{i}} (1)with \overrightarrow{p_{i}} the initial momentum and \overrightarrow{p_{f}} the final momentum. Linear momentum is defined as \overrightarrow{p}=m\overrightarrow{v}, using that on (1):

\varDelta\overrightarrow{p}=m \overrightarrow{v_{f}}-m \overrightarrow{v_{i}} (2)

It's important to note that momentum and velocity are vectors and direction matters, so if +x direction is the direction towards the wall and the -x direction away the wall \overrightarrow{v_{i}}=+2.2\, \frac{m}{s} and \overrightarrow{v_{f}}=-2.2\, \frac{m}{s} so (2) becomes:

\varDelta\overrightarrow{p}=m(-2.2- (+2.2))=-(4.5)(4.4)

\varDelta\overrightarrow{p}=-19.8\, \frac{mkg}{s}

8 0
3 years ago
What are two ways you can increase power by climbing the stairs?
Nina [5.8K]

Answer:

change the

  • time
  • distance
  • force.

Explanation:

P = W/time

W = F*d

You have control over how fast you go up the stairs.

You also have control over how far up the stairs you go.

Therefore the answer is

  • time
  • distance

If you don't like distance as an answer, you can carry something up the stairs -- anything that increases F will do.

8 0
3 years ago
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o
Margarita [4]

Answer:

V_{average} = \frac{1}{2}  V_o  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = \left \{ {{V=V_o \ \ \  t<  \tau /2} \atop {V=0 \ \  \ \  t> \tau /2 }   } \right.

to substitute in the equation let us separate the into two pairs

             V_average = \int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt

             V_average = V_o \ \int\limits^{1/2}_0 {} \, dt

             V_{average} = \frac{1}{2}  V_o

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

6 0
3 years ago
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