Answer:
Check explanation
Explanation:
NB: In this question, we need the mass which is not given,so we have to make assumptions for the mass of xenon.
V^2(rms)= 3KT/m----------------------------------------------------------------------------------(1).
Where k= Boltzmann's constant =1.381×10^−23 m^2.kg/s^2.K.
T= temperature of the gas (in Kelvin), m= mass of one molecule of the gas (in kg).
Temperature, T= 273+(-52) =221K and V= the root mean square (rms).
Assuming that one mole of the gas has ;
m=0.084 kg. Hence, the mass of one molecule using Avagadro's number is;
0.084 kg ÷ 6.02×10^23 molecule.
Therefore, mass,m= 1.395× 10^ -25.
Therefore, from equation one above, we have;
V^2(rms)= 3 × 1.381×10^-23×221k/1.395×10^25.
V^2(rms) = 9.15603×10^-21/ 1.395×10^-25.
V(rms)= √ 6.56346236559139× 10^−46.
V(rms)= 2.56×10^-23 m/s.
