Answer:
3.125 × 10¹³ Electrons
Explanation:
Data provided in the question:
Charge per unit length on rod = 0.00500 C/m
Length of the rod = 1 mm = 1 × 10⁻³ m
Therefore, the total charge on the rod
= Charge per unit length on rod × Length of the rod
= 0.00500 C/m × ( 1 × 10⁻³ m)
= 5 × 10⁻⁶ C
Thus,
Number of electrons removed
= total charge on the rod ÷ Charge of an electron
= 5 × 10⁻⁶ ÷ (1.6 × 10⁻¹⁹)
= 3.125 × 10¹³ Electrons
answer:
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Answer:
Potassium iodide increases the decomposition rate of hydrogen peroxide.
Explanation:
Potassium iodide increases the decomposition rate of hydrogen peroxide because potassium iodide act as a catalyst. A catalyst speed up the process of chemical reaction without reacting with the molecules present in reaction. If the potassium iodide is not present as a catalyst for the decomposition of hydrogen peroxide then the decomposition of hydrogen peroxide takes too much time because the catalyst is absent that speed up the reaction.
Answer:
X has 9 Electrons, 9 Protons and 10 Neutrons
X is Fluorine
Explanation:
19 in X is Nucleon number
So, if you minus 19 by 9 down there (which is proton number) you'll get 10 (Neutron number).
Now, Proton = Electron. That's why Electron is 9 too. I figured that X is Fluorine bcuz it has 9 Electrons. If you venture around in the periodic table, fluorine is the ninth element innit.
hope this helps ya ＼(^o^)／
Answer:
159 mg caffeine is being extracted in 60 mL dichloromethane
Explanation:
Given that:
mass of caffeine in 100 mL of water = 600 mg
Volume of the water = 100 mL
Partition co-efficient (K) = 4.6
mass of caffeine extracted = ??? (unknown)
The portion of the DCM = 60 mL
Partial co-efficient (K) = 
where; 
solubility of compound in the organic solvent and 
= solubility in aqueous water.
So; we can represent our data as:
÷ 
Since one part of the portion is A and the other part is B
A+B = 60 mL
A+B = 0.60
A= 0.60 - B
4.6=
÷ 
4.6 = 
4.6 × =
4.6 B 
= 0.6 - B
2.76 B = 0.6 - B
2.76 + B = 0.6
3.76 B = 0.6
B = 
B = 0.159 g
B = 159 mg
∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.
