Question

A cylindrical canister contains 3 tennis balls. Its height is 8.75inches, and its radius is 1.5. The diameter of one tennis ball is 2.5. How much of the canister’s volume is unoccupied by tennis balls? Use 3.14 for π, and round your answer to the nearest hundredths place.

Answer 1

37.29in (cubed, so put the exponent 3 after inches)

Answer 2

Answer:

The canister’s volume is unoccupied by tennis balls is 37.28 inches cube.

Step-by-step explanation:

Given : A cylindrical canister contains 3 tennis balls. Its height is 8.75 inches, and its radius is 1.5. The diameter of one tennis ball is 2.5.

To find: How much of the canister’s volume is unoccupied by tennis balls?

Solution :

The tennis ball is in sphere shape.

The diameter of one tennis ball is 2.5.

The radius of one tennis ball is $\frac{2.5}{2}=1.25$.  

The volume of 1 tennis ball is $V=\frac{4}{3}\pi r^3$

$V=\frac{4}{3}(3.14) (1.25)^3$

$V=\frac{4}{3}(3.14)(1.953125)$

$V=8.177 in^3$

Volume of 3 Tennis ball is

$V=8.177\times 3=24.53 in^3$

A cylindrical canister - height is 8.75 inches and radius is 1.5.

The volume of the cylindrical canister is $v=\pi r^2h$

$v=(3.14)(1.5)^2(8.75)$

$v=(3.14)(2.25)(8.75)$

$v=61.81875 in^3$

Unoccupied space is

$S= v-V$

$S= 61.81-24.53$

$S= 37.28in^3$

The canister’s volume is unoccupied by tennis balls is 37.28 inches cube.