Multiply field strength (N/kg) by mass (kg) to get weight (N)
At the start, the car is carrying
4.7 kg * (9.8 N/kg) = 46.06 N
of fuel.
At the end, it is carrying
3.0 kg * (9.8 N/kg) = 29.4 N.
Assuming the car remains completely intact, its weight was reduced by
46.06 N - 29.4 N = 16.66 N.
Answer:
E = 0.13 J
Explanation:
At resonance condition we have
now if the frequency is double that of resonance condition then we have
now we have
now average power is given as
Now time period is given as
so total energy consumed is given as
In technical terms, every coil of wire increases the "magnetic flux density" (strength) of your magnet.
So it's A (magnetic field increase)
Given:
The power is
The voltage is
The resistance is
To find:
a) the current
b) the power loss
c) the percent loss
Explanation:
a) The current is,
Hence, the current is 6.21 kA.
b)
The power loss is,
Hence, the power loss is 57.8 MW.
c)
The percentage loss is
Hence, the power loss percentage is 32.1 %.