Answer:
Explanation:
a )
If it is totally absorbed pressure is calculated as follows .
Pressure = I / c where I is intensity of light falling .
= 1000 / 3 x 10⁸
= 3.33 x 10⁻⁶ N / m²
b ) weight of tritium atom
= 3 x 1.67 x 10⁻²⁷ kg
acceleration = force / mass
= 3.33x 10⁻⁶ / 3 x 1.67 x 10⁻²⁷
= .6646 x 10²¹ m /s²
= 66.46 x 10¹⁹ m / s²
Explanation:
Given that,
Bill is riding his bicycle at 5 m/s eastward: and Carlos is driving his car at 15 m/s westward.
Taking eastward as positive direction, we have:
is the velocity of Bill with respect to Amy (which is stationary)
is the velocity of Carlos with respect to Amy.
Bill is moving 5 m/s eastward compared to Amy at rest, so the velocity of Bill's reference frame is
Therefore, Carlos velocity in Bill's reference frame will be
So, the magnitude is 20 m/s and the direction is westward (negative sign).
From the average speed you can fix an equation:
Average speed = distance / time
You know the average speed = 65.1 kg / h, then
65.1 = distance / total time,
where total time is the time traveling plus 22.0 minutes
Call t the time treavelling and pass 22 minutes to hours:
65.1 = distance / [t + 22/60] ==> distance = [t + 22/60]*65.1
From the constant speed, you can fix a second equation
Constant speed = distance / time traveling
94.5 = distance / t ==> distance = 94.5 * t
The distance is the same in both equations, then you have:
[t +22/60] * 65.1 = 94.5 t
Now you can solve for t.
65.1t + 22*65.1/60 = 94.5t
94.5t - 65.1t = 22*65.1/60
29.4t = 23.87
t = 23.87 / 29.4
t = 0.812 hours
distance = 94.5 km/h * 0.812 h = 76.7 km
Answers: 1) 0.81 hours, 2) 76.7 km
Use a=(dv/dt) (change in velocity/ change in time)=acceleration
(1.2/5)=acceleration
F=ma (Newton's second law, Force= Mass x Acceleration
=960 x 0.24 F=230.4N If T<230.4N then the tow rope will hold
Answer:
Explanation:
Force, F = - mg j
r = - 7x i + y j
Torque is defined as the product f force and the perpendicular distance.
It is also defined as the cross product of force vector and the displacement vector.
[tex]\overrightarrow{\tau }= 7 m g x k
Here, we observe that the torque is independent of y coordinate.
