1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
JulijaS [17]
3 years ago
8

Please help.

Chemistry
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

1. a series of steps 2. experiment

Explanation:

You might be interested in
If you produced 76.10 grams of potassium chloride in the reaction how many grams of potassium were required?
11111nata11111 [884]

Answer:39.8375

Explanation:

The mole for the equation is 1:1

Then the molar mass of KCl is 74.5g

Molar mass of k is 39

74.5g of KCl gives 39g of k

76.10g of KCl gives xg of k

X= 76.10×39/74.5

X= 2967.9/7

X= 39.8375

6 0
3 years ago
Help with this please.
chubhunter [2.5K]

Answer:

a

Explanation:

cause its a tell me if you get it right hsnsnsjsjsjsnanajaksks bshsjjssjjsjddjhs h sshheggduejnd uhh cig jsjdufudneidisjsjjshhshshshhzhshjdhdudjsjdjdjdjdjdjdjsjsjsjsjsjsjdjdjsiiddudjdjdjsjdjjdjduxixuxixxuchucucufididididjdhxuueudhh see h bj too yxhxuxjdjsjsu

6 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

<u>No of moles = mass of the substance÷molar mass of the substance</u>

No of moles of carbon = 14.4 /12= 1.2 moles

No of moles of O2 = Mass of reacted O2/Molar mass of O2.

No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

Mass of CO2 produced(x) = 1.2 x 44 = 52.8 g

<u>Thus 52.8 g of CO2 is produced.</u>

5 0
3 years ago
How to classify hemicetal and acetal
kumpel [21]
You might have meant hemiacetal, not hemicetal.
Acetals contain two –OR groups, one –R group and a –H atom. In hemiacetals, one of the –OR groups in acetals is replaced by a –OH group<span>.
</span>
3 0
3 years ago
1 pt
Degger [83]
Ghbghvdezagnlmhhbbb
4 0
2 years ago
Other questions:
  • the absolute tempeature of a gas is increased four times while maintaining a constant volume. what happens to the pressure of th
    14·1 answer
  • What happens when an atom gains an electron
    15·2 answers
  • Which of the following statements is not true regarding physical properties and changes?
    5·2 answers
  • Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu
    14·1 answer
  • A mixture of gases at a total pressure of 95 kPa contains nitrogen, carbon dioxide and oxygen. The partial pressure of carbon di
    5·2 answers
  • Calculate the pH of the following?
    5·1 answer
  • Uniformitarianism states that the geologic processes occurring in the past are the same processes that are occurring today.
    8·2 answers
  • How has modern research in<br> chemistry impacted society?
    6·1 answer
  • Need answer for 9.0mm x 2.0mm x 2.0mm
    14·1 answer
  • How much water must be added to 6.0 M silver nitrate in order to make 500 mL of 1.2 M solution?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!