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iren [92.7K]
3 years ago
7

A chemical reaction is carried out in a closed container. The energy absorbed by the chemical reaction is 50 kJ. What is the ene

rgy liberated from the air or the walls of the container?
A)50 kJ
B)75 kJ
C)25 kJ
D)100 kJ
Chemistry
1 answer:
Contact [7]3 years ago
8 0

Answer:

A) 50 kJ.

Explanation:

  • According to the law of conservation of energy that energy can not be destroyed or created from nothing but it can be converted from one form to another.
  • In a closed system; the amount of heat released by a part of the system is equal to the amount of heat absorbed by other parts of the system.

<em>Q released = Q absorbed.</em>

<u><em>So, the energy liberated from the air or the walls of the container is 50 kJ.</em></u>

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The number of moles in 4.27×10^22 particles of silver is
bazaltina [42]

Answer:

mol=0.0709mol

Explanation:

Hello,

In this since one mole equals 6.022x10²³ particles of silver by means of the Avogadro's number, we can compute the moles in 4.27x10²² particles as shown below:

mol=4.27x10^{22}particles*\frac{1mol}{6.022x10^{23}particles}\\\\mol=0.0709mol

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3 0
3 years ago
A chemist determines by measurements that moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrog
Likurg_2 [28]

Answer:

0.56 g

Explanation:

<em>A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.</em>

Step 1: Given data

Moles of nitrogen gas (n): 0.020 mol

Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

We will use the following expression.

m = n × M

m = 0.020 mol × 28.02 g/mol

m = 0.56 g

4 0
3 years ago
Which part of the atom is involved in bonding?
bonufazy [111]

Answer:

Valence electrons (the electrons on the outermost shell of the atom) are responsible for bonding

Explanation:

8 0
3 years ago
A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation
qaws [65]

Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its <em>wavelength</em> and <em>temperature</em> is given by Wien's displacement law.

\lambda_{max}=\frac{b}{T}

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K  }{0.21m} =0.014K

8 0
3 years ago
Use the periodic table to determine the electron configuration for Ca and Pm in noble-gas notation Ca: [Ar]4s2 [Ar]4s1 [Ar]3s2 [
sveta [45]
Answer:

1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵

Explanation:

1) Ca:

Its atomic number is 20. So it has 20 protons and 20 electrons.

Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.

So, you have two more electrons (20 - 18 = 2) to distribute.

Those two electrons go the the orbital 4s.

Finally, the electron configuration is [Ar] 4s².

2) Pm

The atomic number of Pm is 61, so it has 61 protons and 61 electrons.

Pm is in the row (period) 6. So, the noble gas before Pm is Xe.

The atomic number of Xe is 54.

Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.

The resultant distribution for Pm is: [Xe]6s² 4f⁵.
5 0
3 years ago
Read 2 more answers
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