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Y = (x)^(1/9)*Find f(x) when x=(1/2)Round your answer to the nearest thousandth.

Verizon [17]

We are given a function f ( x ) defined as follows:

$y=f(x)=x^{\frac{1}{9}}$

We are to determine the value of f ( x ) when,

$\times\text{ = }\frac{1}{2}$

In such cases, we plug in/substitue the given value of x into the expressed function f ( x ) as follows:

$y\text{ = f ( }\frac{1}{2}\text{ ) = (}\frac{1}{2})^{\frac{1}{9}}$

We will apply the power on both numerator and denominator as follows:

$f(\frac{1}{2})=\frac{1^{\frac{1}{9}}}{2^{\frac{1}{9}}}\text{ = }\frac{1}{2^{\frac{1}{9}}}$

Now we evaluate ( 2 ) raised to the power of ( 1 / 9 ).

$f\text{ ( }\frac{1}{2}\text{ ) = }\frac{1}{1.08005}$

Next apply the division operation as follows:

$f\text{ ( }\frac{1}{2})\text{ = }0.92587$

Once, we have evaluated the answer in decimal form ( 5 decimal places ). We will round off the answer to nearest thousandths.

Rounding off to nearest thousandth means we consider the thousandth decimal place ( 3rd ). Then we have the choice of either truncating the decimal places ( 4th and onwards ). The truncation only occurs when (4th decimal place) is < 5.

However, since the (4th decimal place) = 8 > 5. Then we add ( 1 ) to the 3rd decimal place and truncate the rest of the decimal places i.e ( 4th and onwards ).

The answer to f ( 1 / 2 ) to the nearest thousandth would be:

$\textcolor{#FF7968}{f}\text{\textcolor{#FF7968}{ ( }}\textcolor{#FF7968}{\frac{1}{2})}\text{\textcolor{#FF7968}{ = 0.926}}$

6 0

7 months ago

Rob ate 3 cookies and drank 2 cups of milk. Barry ate 8 cookies and drank 1 cup of milk. Kevin ate 9 cookies and drank 4 cups of

harkovskaia [24]

<h3><u>Cookies</u></h3>

Rob: 3

Barry: 8

Kevin: 9

Let's add all of that up.

3 + 8 + 9

11 + 9

= 20 cookies total

Rob: 2

Barry: 1

Kevin: 4

Let's add this up.

2 + 1 + 4

3 + 4

= 7 cups of milk

They had 20 cookies and 7 cups of milk before they ate.

8 0

3 years ago

Read 2 more answers

A homeowner wants several small dormers built on his roof to admit light. They will be in the shape of isosceles triangles whose

Vlad1618 [11]

P = s + (s + 5) + (s + 5) This represents the two sides that are 5 inches longer than the base (s + 5) and the base (s).
Simplifying.
100 = 3s + 10
subtract 10 from both sides
90 = 3s
divide both sides by 3
30 = s
base = 30
sides = 35

CHECK 30 + 35 + 35 = 100

4 0

3 years ago

Which statement about the value of x is true? x > 38 x < 39 x < 77 x > 103

grigory [225]

Answer:

Second one

Step-by-step explanation:

3 0

2 years ago

Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide

hichkok12 [17]

Answer:

A 99% confidence interval will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

The 95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

From the above equation we see that

$E \ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Here $Z_{\frac{\alpha }{2} }$ is the critical value of the half of the level of significance and this value increase as the confidence level increase

Now if a 99% confidence level is used , it then means that the value of

$Z_{\frac{\alpha }{2} }$ will increase, this in turn will increase the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval will be wider than a 95% confidence interval

5 0

2 years ago