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3 years ago

How many Mg atoms are presented in 3.00 moles of MgCl2

Chemistry

1 answer:

ella [17]3 years ago

3 0

Answer:

1.81 x 10²⁴ atoms

Explanation:

To find the number of atoms in the given number of moles, we need to understand that every substance contains the Avogadro's number of particles.

More appropriately, a mole of any substance will contain the Avogadro's number of particles which is 6.02 x 10²³ atoms

So;

If 1 mole of a substance = 6.02 x 10²³ atoms;

3 mole of MgCl₂ will contain 3 x 6.02 x 10²³ = 1.81 x 10²⁴ atoms

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Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

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End of the Day = -6°Centigrade. (Final temperature)

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Solution:

We will have,

$\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}$

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3 years ago

Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy

barxatty [35]

Answer:

1. $S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

2. $Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

3.The electron affinity of $Mg^{2+}$ is zero.

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Explanation:

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of $S^{-}$ is as follows.

$S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

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Amount of energy required to removal of an electron from an isolated gaseous atom.

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$O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

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