Answer: -39.2 m/s or 39.2 m/s directed downwards
Explanation:
This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero
, and the acceleration is constant (acceleration due gravity).
So, in order to calculate the final velocity
of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:

Where:
is the acceleration due gravity (directed downwards)
is the time it takes to the rock to fall down the cliff

This is the rock's final velocity and its negative sign indicates it is directed downwards
Answer:
if the frequency of the wave if tripled then period of wave gets tripled
You must observe the object twice.
-- Look at it the first time, and make a mark where it is.
-- After some time has passed, look at the object again, and
make another mark at the place where it is.
-- At your convenience, take out your ruler, and measure the
distance between the two marks.
What you'll have is the object's "displacement" during that period
of time ... the distance between the start-point and end-point.
Technically, you won't know the actual distance it has traveled
during that time, because you don't know the route it took.
a)
• P = F/A
P = pressure = 630 N/m^2
F = force
A = area
F = mg = 0.50 kg x 9.8 m/s^2 = 4.9 N
m= mass
g= gravity
P = F/A
A = F/P
A = 4.9 N / 630 N/m^2 = 7.778 x 10^-3 m^2
b)
• Area of a circle = pi* radius ^2
7.778 x 10^-3 m^2 = pi* radius ^2
√(7.778 x 10^-3 m^2 / pi ) = radius
radius = 0.04976 m
Answers:
a ) 7.778 x 10^-3 m^2
b) 0.04976 m