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boyakko [2]
2 years ago
11

The big bang theory suggests that our universe formed as the result of a huge explosion that sent all existing matter flying out

ward from a single point. The big bang theory is supported by which of these observations?.
Physics
1 answer:
marin [14]2 years ago
4 0

Answer:

All galaxies appear to be moving away from all other galaxies

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Two small conducting point charges, separated by 0.4 m, carry a total charge of 200 C. They repel one another with a force of 12
Lunna [17]

Answer:

200 C

Explanation:

Let C1 and C2 be their charges. According to Coulomb's law

F_C = k\frac{C_1C_2}{R^2}

where k = 8.99\times10^9 nm^2/C^2 is the constant, R = 0.4m is the distance between them, F = 120 N is their resulting charge force

120 = 8.99\times10^9\frac{C_1C_2}{0.4^2}

C_1C_2 = \frac{120*0.4^2}{8.99\times10^9} = 2.13\times10^{-9}

Since their total charge is 200C:

C_1 + C_2 = 200 or C_1 = 200 - C_2

We can substitute the above equation

C_1C_2 = (200 - C_2)C_2 = 2.13\times10^{-9}

-C_2^2 +200C_2 - 2.13\times10^{-9} = 0

C= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

C= \frac{-200\pm \sqrt{(200)^2 - 4*(-1)*(-0.00000000213)}}{2*(-1)}

C= \frac{-200\pm200}{-2}

C = 1.06 \times 10^{-11} or C \approx 200

So the larger charge is C = 200 C

8 0
4 years ago
True or False: The absorption of alcohol can be slowed down by eating, but only water can reduce the BAL level.
lesya [120]
A hopes this helps idk this
3 0
3 years ago
Read 2 more answers
The energy levels of one‑electron ions are given by the equation En=(−2.18×10−18 J)(Z^2/n^2) where Z is atomic number and n is t
Alexxandr [17]

Answer:

\lambda=4.86*10^{-7}m

Explanation:

Using the given equation, we calculate the energy associated with the excited state n_i=8 and n_f=4

E_n=\frac{-2.18*10^-18J(Z^2)}{n^2}

Helium has an atomic number (Z) equal to 2, for n=8:

E_8=\frac{-2.18*10^{-18}J(2^2)}{8^2}\\E_8=-1.36*10{-19}J

For n=4:

E_4=\frac{-2.18*10^{-18}J(2^2)}{4^2}\\E_4=-5.45*10{-19}J

When an electron jumps from an energy level with greater energy E_i to one with lower energy E_f the wavelength of the emitted photon is given by:

\lambda=\frac{hc}{E_i-E_f}

h is the Planck constant and c the speed of light in vaccum. So, we have:

\lambda=\frac{hc}{E_8-E_4}\\\lambda=\frac{6.63*10^{-34}J \cdot s(3*10^8\frac{m}{s})}{-1.36*10{-19}J-(-5.45*10{-19}J)}\\\lambda=4.86*10^{-7}m

5 0
3 years ago
Ano ang iyong masasalamin sa relihiyon?​
Nutka1998 [239]

Answer:

si y mas ya que lo sobrevalorado es mas que suficiente en el aspecto de todo

6 0
3 years ago
An orchestra is practicing a piece that is to be played at an allegro tempo. The conductor sets a metronome at 160 beats per min
omeli [17]

Answer:

375 ms

Explanation:

the frequency of metronome , f = 160 beats per minute

f = 160 /60 beats per sec

f = 2.67 beats /s

the period of a single beat , T = 1/f

T = 1/2.67 s

T = 0.375 s = 375 ms

the period of a single beat is 375 ms

3 0
3 years ago
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