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1 year ago

11

The big bang theory suggests that our universe formed as the result of a huge explosion that sent all existing matter flying out

ward from a single point. The big bang theory is supported by which of these observations?.

1 answer:

marin [14]1 year ago

4 0

Answer:

All galaxies appear to be moving away from all other galaxies

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A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2

KengaRu [80]

Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

$R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m$

Therefore, the length of the wire is 134.62 m.

6 0

2 years ago

The speed of a tennis ball that is served is 73.14 m/s. During a serve, the ball typically starts from rest and is in contact wi

Serga [27]

Answer: Third option

F = 250w

Explanation:

The impulse can be written as the product of force for the time interval in which it is applied.

$I = F (t_2-t_1)$

You can also write impulse I as the change of the linear momentum of the ball

$I = mv_2 -mv_1$

So:

$F (t_2-t_1) = mv_2 -mv_1$

We want to find the force applied to the ball. We know that

$(t_2-t_1) = 30$ milliseconds = 0.03 seconds

The initial velocity $v_1$ is zero.

The final speed $v_2 = 73.14\ m / s$

So

$F * 0.03 = 73.14m$

$F * 0.03 = 73.14m\\\\F=\frac{73.14m}{0.03}\\\\F=2438m$

We must express the result of the force in terms of the weight of the ball.

We divide the expression between the acceleration of gravity

$g = 9.8\ m / s ^ 2$

$F=\frac{2438m*g}{g},\ \ m*g=w\\\\g=9.8\ m/s^2\\\\F=\frac{2438w}{9.8}\\\\F=249w$

The answer is the third option

3 0

2 years ago

An airplane flies eastward and always accelerates at a constant rate. at one position along its path it has a velocity of 26.3 m

galina1969 [7]

We will use the formula / equation to determined the time.

Distance = ½ * (vi + vf) * t
48100 = ½ * (26.3 + 41.9) * t
t = 48100 ÷ 34.1 = 1410.557185 seconds

We will use the formula / equation to determined the acceleration.

vf = vi + a * t
41.9 = 26.3 + a * 1410.557185
a = (41.9 – 26.3) ÷ 1410.557185 = 0.011059459 m/s^2

We will use the formula / equation to determined the acceleration.

vf^2 = vi^2 + 2 * a * d
41.9^1 = 26.3^2 + 2 * a * 48100
a = (41.9^2 – 26.3^2) ÷ 96200 = 0. 011059459 m/s^2
Since both answers are the same, I believe the acceleration is correct.

6 0

3 years ago

Can someone explain the equation <br> Q = M C delta T <br> or Q = MCΔT<br><br> Thanks!

mylen [45]

Q = heat energy , m=mass , c=specific heat , delta T= change in temperature

as you know heat is a form of energy which is <em>usually</em> measured in Joules according to the SI. and also we usually use kilograms for mass.

so you need to know the mass, specific heat, and change in temperature in order to find out the heat energy :)

3 0

2 years ago

Read 2 more answers

The speed of light in a vacuum is approximately 0.3 gm/s. What is the speed of light in meters per second?

klemol [59]

We have to convert Gm/s to m/s.

As $1 \ Gm/s = 10^9 \ m/s$

Therefore the speed of light in vacuum,

$c = 0.3 \ Gm/s = 0.3 \times 10^9 \ m/s \\\\ c= 3 \times 10^8 \ m/s$

Thus, the speed of light in m/s is $3 \times 10^8 \ m/s$

7 0

2 years ago