All categories

3 years ago

According to Newton's second law, force is equal to ______________.

Physics

2 answers:

Shalnov [3]3 years ago

7 0

<h2>Answer:</h2>

Force is equal to mass times acceleration

<h2>Explanation:</h2>

According to second law of Newton when a force is applied on an object, it produces an acceleration in that body and that acceleration is dependent upon the mass of that body. If the mass of the body is more then more force is required to produce an acceleration and vice versa. Mathematically this can be written as

F = m x a

Svetach [21]3 years ago

3 0

Hey there!
The Second Law of Motion by Newton is f = ma, and that means the force of an object is defined by its mass times its acceleration.
Therefore your answer is e.
Hope this helps!

You might be interested in

Given that the frequency of an EM wave is 4THz, what is its wavelength?

Vilka [71]

Answer:

The wavelength of the EM wave is 7.5 * 10⁻⁴ m

Explanation:

The velocity of a wave is related to its wavelength by the following formula;

velocity = wavelength * frequency

For an electromagnetic (EM) wave, its velocity is equal to the velocity of light, c = 3.0 * 10⁸ m/s

Given that the frequency and veloity of the given EM wave in the question is known, its wavelength is calculated as follows:

wavelength = velocity/frequency

where velocity of the EM wave = 3.0 * 10⁸ m/s;

frequency = 4THz = 4 * 10¹² Hz

wavelength = 3.0 * 10⁸m/s / 4 * 10¹² Hz

wavelength = 7.5 * 10⁻⁴ m

Therefore, the wavelength of the EM wave is 7.5 * 10⁻⁴ m

8 0

3 years ago

A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the a

uranmaximum [27]

Answer:

$approx.= 25\frac{m}{s}$

Explanation:

Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:

$a=\frac{V^{2} }{r}$

which allows us to solve for the velocity:

$V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...$

3 0

3 years ago

Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena Kevin, another biker, is

Ulleksa [173]

Answer:

the answer is C

Explanation:

i took the test just now so i am glad i can help someone in the future❣❣❣❣

<u><em>Also here is the explanation</em></u>

Note that the magnitude of acceleration (a) is given by a =

, where v is the speed and R is the radius. Because acceleration is the same for both bikers, the ratio

, also has to be the same for both. Given that Kevin’s speed is higher, the radius of his path must also be higher to maintain the same ratio. Therefore, Kevin’s circular path has a bigger radius than Linda’s path.

8 0

3 years ago

A proton of mass mp is released from rest just above the lower plate and reaches the top plate with speed vp. An electron of mas

vodka [1.7K]

Answer:

$v_e=\sqrt{\frac{m_pv_p^2}{m_e}}$

Explanation:

You can consider that the force that acts over the proton is the same to the force over the electron. This is because the electric force is given by:

$F=qE$

$F_p=F_e$

where E is the constant electric field between the parallel plates, and is the same for both electron and proton. Also, the charge is the same.

by using the Newton second law for the proton, and by using kinematic equation for the calculation of the acceleration you can obtain:

$m_pa_p=qE\\\\a_p=\frac{v_p^2}{2d}\\\\\frac{m_pv_p^2}{2d}=qE$

(it has been used that vp^2 = v_o^2+2ad) where d is the separation of the plates, ap the acceleration of the proton, vp its velocity and mp its mass.

By doing the same for the electron you obtain:

$\frac{m_ev_e^2}{2d}=qE$

we can equals these expressions for both proton and electron, because the forces qE are the same:

$\frac{m_pv_p^2}{2d}=\frac{m_ev_e^2}{2d}\\\\v_e=\sqrt{\frac{m_pv_p^2}{m_e}}$

4 0

3 years ago

You kick a soccer ball with a speed of 18 m/s at an angle of 43. How long does it take the the ball to reach the top of its traj

Sati [7]

Answer:

1.25 s

Explanation:

The motion of the soccer ball is an example of a projectile motion.

So, time taken by the ball to reach the top of the trajectory is exactly half of the total time of flight of the soccer ball.

In a projectile motion, the projectile is thrown at an angle to the ground with some initial velocity. The motion can be divided into two independent direction motions; one in the horizontal direction and the other in the vertical direction.

The time of flight is the time taken by the projectile to reach the ground again.

The formula for time of flight is given as:

$T=\frac{2u\sin \theta}{g}\\Where,T\to \textrm{Time of flight}\\u\to \textrm{Initial velocity of ball}\\\theta \to \textrm{Angle of projection}\\g\to \textrm{Acceleration due to gravity}$

Here, $u=18\ m/s,\theta=43\°,g=9.8\ m/s^2$ . Therefore,

$T=\frac{2\times 18\times \sin 43\°}{9.8}=2.505\ s$

Now, the time taken to reach the top is half of the total time. Therefore,

$T_{top}=\frac{T}{2}=\frac{2.505}{2}=1.25\ s$

Therefore, it takes 1.25 s for the ball to reach the top of its trajectory.

5 0

3 years ago