Answer:
x = –7, x = 2, or x = 4 are factors of f(x).
Step-by-step explanation:
Given : f(x) = 5x³ +5x²-170x +280 and x + 7 is one factor .
To find : What are all the roots of the function.
Solution : f(x) = 5x³ +5x²-170x +280 .
We have given that x + 7 is factor that mean x = -7 is factor of f(x )
When we divide f(x) by x +7 we get
5x² -30x +40 =0
Taking common 5 from equation
5( x² -6x +8) =0
On dividing by 5 both sides
x² -6x +8 = 0
On factoring
x² -2x -4x +8 = 0.
Taking common x from first two terms and -4 from last two terms
x ( x -2) -4 (x -2) = 0
On grouping
(x-2) (x-4) = 0
x -2 =0
x =2
x-4 =0
x = 4
Therefore, x = –7, x = 2, or x = 4 are factors of f(x).
2/3 > 1/5
2/3 = .6666666
1/5 = .2
6 is greater than 2 therefore 2/3 is greater than 1/5
4th term / second term = a1r^3 / a1r = r^2
so r^2 = 45/4 / 20 = 45/80 = 9/16
so r = sqrt 9/16 = 3/4 answer
Answer:
can you please tell me what grade you're in like
what is
Answer: 2.5 or 2 1/2.
Step-by-step explanation:
