Solve for .x. 2r - 12 9 x +9

. John has two coupons to use at a clothing store. One is for $20 off and the other is for 20% off. John wants to purchase a shi

zlopas [31]

Complete question :

John has two coupons to use at a clothing store. One is for $20 off and the other is for 20% off. John wants to purchase a shirt with one of the coupons and wants to pay the least amount that he can. Choose the answer that BEST describes the situation. * 1 point A. The shirt will have the lowest price with the $20 off coupon. B. The shirt will have the lowest price with the 20% off coupon. C. The shirt will cost the same with either coupon. D. It depends on the cost of the shirt as to which coupon will help John pay the lowest price.

Answer: D. It depends on the cost of the shirt as to which coupon will help John pay the lowest price.

Step-by-step explanation:

Given two different coupon options :

First: 20% off

Second = $20 off

To our hase with one which enables one to pay the amount of money :

The price of the shirt will determine which of the coupons will give the least amount. For instance, a shirts which which cost below $100 will require the $20 off coupon in other to attain the least payment amount. However for shirts which cost above $100, the 20% coupon yield the least amount. Shirts which cost $100. Both coupons yields the same discount amount.

6 0

3 years ago

Jon and Becky measured the circle-shaped part of a sun they drew on the sidewalk.

PIT_PIT [208]

Answer: The approximate area of the circle is: 3,629.84 cm² .
______________________________________________________
Area of a circle, "A" : A = π * r² ;

in which: A = Area of circle ;
π ≈ 3.14 ;
 r = radius;

radius of a circle, "r" = d / 2 ; in which: "d = diameter" ;

Given "d = 64 cm " ;

r = d / 2 = 64 cm / 2 = 32 cm ;
____________________________________________
So; A = π * r² ;

A ≈ (3.14) * (32 cm)² ;

A ≈ (3.14) * (1156 cm²) ;
_____________________________________________

A ≈ 3,629 .84 cm² .
_____________________________________________

3 0

2 years ago

Suppose the interval [negative 3−3,negative 1−1] is partitioned into nequals=44 subintervals. What is the subinterval length

Kobotan [32]

Answer: Δx = 0.5

Step-by-step explanation:

We have the interval:

[−3, −1]

and we partition it into 4 equal intervals.

first, the range of our interval is equal to the difference between the extremes, this is:

-1 - (-3) = -1 + 3 = 2

Then, if we divide it into 4, we have 4 segments with a range of:

2/4 = 0.5

Then the subinterval delta is 0.5, and the 4 intervals are:

[−3, -2.5], [−2.5, −2], [−2, −1.5], [−1.5, −1]

6 0

3 years ago

2ᵃ = 5ᵇ = 10ⁿ. Show that n = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Ba%20%2B%20b%7D%20" id="TexFormula1" titl

11Alexandr11 [23.1K]

There are two ways you can go about this: I'll explain both ways.

Solution 1: Using logarithmic properties
The first way is to use logarithmic properties.

We can take the natural logarithm to all three terms to utilise our exponents.

Hence, ln2ᵃ = ln5ᵇ = ln10ⁿ becomes:
aln2 = bln5 = nln10.

What's so neat about ln10 is that it's ln(5·2).
Using our logarithmic rule (log(ab) = log(a) + log(b),
we can rewrite it as aln2 = bln5 = n(ln2 + ln5)

Since it's equal (given to us), we can let it all equal to another variable "c".

So, c = aln2 = bln5 = n(ln2 + ln5) and the reason why we do this, is so that we may find ln2 and ln5 respectively.

c = aln2; ln2 = $\frac{c}{a}$
c = bln5; ln5 = $\frac{c}{b}$

Hence, c = n(ln2 + ln5) = n( $\frac{c}{a}$ + $\frac{c}{b}$ )
Factorise c outside on the right hand side.

c = cn( $\frac{1}{a}$ + $\frac{1}{b}$ )
1 = n( $\frac{1}{a}$ + $\frac{1}{b}$ )
$\frac{1}{n}$ = $\frac{1}{a}$ + $\frac{1}{b}$

$\frac{1}{n}$ = $\frac{a + b}{ab}$
and thus, n = $\frac{ab}{a + b}$

Solution 2: Using exponent rules
In this solution, we'll be taking advantage of exponents.

So, let c = 2ᵃ = 5ᵇ = 10ⁿ
Since c = 2ᵃ, 2 = $\sqrt[a]{c}$ = $c^{\frac{1}{a}}$

Then, 5 = $c^{\frac{1}{b}}$
and 10 = $c^{\frac{1}{n}}$

But, 10 = 5·2, so 10 = $c^{\frac{1}{b}}$ · $c^{\frac{1}{a}}$
∴ $c^{\frac{1}{n}}$ = $c^{\frac{1}{b}}$ · $c^{\frac{1}{a}}$

$\frac{1}{n}$ = $\frac{1}{a}$ + $\frac{1}{b}$
and n = $\frac{ab}{a + b}$

4 0

3 years ago

Which digit is in the hundreds place in 3,254,107

ozzi

The 1 is in the hundreds place good luck!!!

5 0

3 years ago