A transverse wave is traveling through a canal. If the distance between two successive crests is 3.17 m and four crests of the w ave pass a buoy along the direction of travel every 22.6 s, determine the following. (a) frequency of the wave
1 Hz
(b) speed at which the wave is traveling through the canal
2 m/s
1 answer:
Answer:
a. 0.18Hz
b. 0.56m/s
Explanation:
From the question we can deduct the following parameters
The wavelength, λ is define as the distance between two successful crest or trough and from the question we conclude that wavelength is 3.17m.
Also the period of the wave T can be computed as
T=22.6/4
T=5.65secs.
a. To compute the frequency, recall that frequency, F=1/period.
Hence,
F=1/5.65
F=0.18Hz
b. Next we compute the wave speed.
Wave speed=frequency *wavelength
Wave speed =0.18*3.17
Wave speed =0.56m/s
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D all of the above applies to the functions of the nervous system.
Answer:
88200 Pa
it is because
height =9m
density=1000kg/m(cube)
gravity = 9.8m/s(square)
now,
P=d×g×h
= 1000×9.8×9
=88200pa
Answer:
A) 80 N
Explanation:
The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.