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Sedaia [141]
4 years ago
10

WILL MARK BRAINLIEST PLS HELP

Physics
1 answer:
KiRa [710]4 years ago
4 0

Answer:

Our planet's rotation produces a force on all bodies moving relative to theEarth. Due to Earth's approximately spherical shape, this force is greatest at the poles and least at the Equator. The force, called the "Coriolis effect," causes the direction of winds and ocean currents to be deflected.

Hope this helps!

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A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a
aleksklad [387]

Answer:

V=9.2565m/s

Explanation:

From the question we are told that:

Force F = 34 N  

Time t = 0.6 s

Length of pedal l_p=16.5cm \approx0.165m

Radius of wheel r = 33 cm = 0.33 m

Moment of inertia, I = 1200 kgcm2 = 0.12 kg.m2

Generally the equation for Torque on pedal \mu is mathematically given by

\mu=F*L\\\mu=34*0.165

\mu=5.61N.m

Generally the equation for  angular acceleration \alpha is mathematically given by

 \alpha=\frac{\mu}{l}

 \alpha=\frac{5.61}{0.12}

 \alpha=46.75

Therefore Angular speed is \omega

\omega=\alpha*t

\omega=(46.75)*(0.6)

\omega=28.05rad/s

Generally the equation for  Tangential velocity V is mathematically given by

V=r\omega

V=(0.33)(28.05)

V=9.2565m/s

 

5 0
3 years ago
If 478 watts of power are used in 14 seconds,how much work was done
zepelin [54]

Answer:

6692J

Explanation:

Power is defined as the rate at which work is being done.

So,

    Power  = \frac{workdone}{time }  

  Work done  = Power x time

Given parameters:

Power  = 478watts

Time  = 14s

So;

 Work done  = 478 x 14  = 6692J

6 0
3 years ago
A ball is thrown vertically upward with a
Veronika [31]

Answer:

1) The maximum height reached is approximately 39.715 m

2) The time it takes the ball to reach the its highest point is approximately 2.85 s

Explanation:

1) The vertical velocity of the ball, u = 27.9 m/s

The acceleration due gravity, g = 9.8 m/s²

The kinematic equation that gives the height, h, reached by the ball is given as follows;

v² = u² - 2·g·h

Where;

v = The final velocity of the ball = 0 m/s at the maximum height

h = The height reached by the ball = h_{max} at maximum height

Therefore, by substitution of the known values, we have;

v² = u² - 2·g·h

0² = 27.9² - 2 × 9.8 × h_{max}

2 × 9.8 × h_{max} = 27.9²

h_{max} = 27.9²/(2×9.8) ≈ 39.715

The maximum height reached = h_{max} ≈ 39.715 m

2) From the kinematic equation of motion, v = u - g·t, we have the time, t, it takes the ball to reach the maximum height given as follows

At maximum height, the final velocity, v = 0 m/s, therefore, we have;

0 = 27.9 - 9.8 × t

9.8 × t = 27.9

t = 27.9/9.8 ≈ 2.85

The time it takes the ball to reach the maximum height = t ≈ 2.85 seconds.

6 0
3 years ago
Find the initial velocity
Alla [95]

Answer:

A car accelerates uniformly from 5m/s to 10m/s in 5s ...

A car starts from rest and picks up a velocity of 20 m/s ...

A car accelerates uniformly from 10m/s to 20m/s in 5 ...

How much work is required to accelerate a 1000 kg car ...

More results from<u> www.quora.com</u>

Explanation:

4 0
3 years ago
A person throws a 10kg rock straight up. If the person exerted 3500N of force on the rock over a distance
pickupchik [31]

Answer:

h = 17.83[m]

Explanation:

By means of the working equation which is equal to the product of force by distance, we can find the energy printed at the launch.

W=F*d

where:

W = work [J]

F = force = 3500 [N]

d = distance = 0.5 [m]

Now replacing:

W= 3500*0.5\\W=1750[J]

Now, this same work is converted to kinetic energy, necessary for the body to move with an initial velocity. And by energy conservation, we can say that kinetic energy is transformed into potential energy. That is, the kinetic energy will be equal to the potential energy.

W=E_{kin}=E_{pot}

where:

Ekin = kinetic energy [J]

Epot = potential energy [J]

Therefore:

1750 = m*g*h\\1750=10*9.81*h\\h = 17.83[m]

4 0
3 years ago
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