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elixir [45]
3 years ago
6

DNA instructions: GCCUAAUGCCCGAGUAACACC GGU TRANSCRIBE THE ABOVE DNA PATTERN into mRNA message​

Chemistry
1 answer:
Katarina [22]3 years ago
7 0

CGGAUUACGGGCUCAUUGUGGCCA

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Can you guys help me :) ?<br>winner takes all​
posledela

Answer:

1. Ag2CO3

2.Ba3(PO4)2

3. Cu(OH)2

4. AL

Explanation:

5 0
3 years ago
What is the mass of an object if force of -136 n can make it accelerate at -9.6 m/s^2
vampirchik [111]

The answer for the following problem is mentioned below.

  • <em><u>Therefore the mass of an object is 14.16 grams.</u></em>

Explanation:

Force:

The push or pull on an object with mass that cause change in the velocity

It is a vector quantity.

The formula to calculate the force is:

F = m × a

Given:

Force (F) = -136 N

acceleration (a) = -9.6 m/s^2

To calculate:

mass of the object (m)

We know that,

<em>F = m × a</em>

where,

F represents the force of the object

m represents mass of an object

a is acceleration of an object

From the equation;

-136 = m × -9.6

m = \frac{-136}{-9.6}

m = 14.16 grams

<em><u>Therefore the mass of an object is 14.16 grams.</u></em>

3 0
4 years ago
Nuclear power produces more toxic mercury than coal-burning power plants do.<br><br> True Or False?
andre [41]
True because it has more power than coal burning
3 0
3 years ago
Read 2 more answers
HELP LAST QUESTION WILL MAKE BRAINLIEST
Alenkasestr [34]

Answer:

I think it is C.)????

4 0
3 years ago
How much heat is absorbed during production of 147 g of NO by the combination of nitrogen and oxygen?
marin [14]

Answer:

\large \boxed{\text{105 kcal}}

Explanation:

MM:                        30.01

            N₂ + O₂ ⟶ 2NO; ΔH = +43 kcal/mol

m/g:                         147

Treat the heat as if it were a reactant in the reaction. Then you can write

N₂ + O₂ + 43 kcal ⟶ 2NO

The conversion factor is then 43 kcal/2 mol NO.

1. Moles of NO

\text{Moles of NO} = \text{147 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{4.898 mol NO}

2. Amount of heat

\text{Heat} = \text{4.898 mol NO } \times \dfrac{\text{43 kcal}}{\text{2 mol NO}} = \text{105 kcal}\\\\\text{The reaction absorbs $\large \boxed{\textbf{105 kcal}}$}

7 0
3 years ago
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