The oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
<h3>What is an oxidizing and reducing agent?</h3>
An oxidizing agent is any substance that oxidizes, or receives electrons from another substance and as a result, becoming reduced.
On the other hand, a reducing agent is any substance that reduces or donates electrons to another and as a result becomes oxidized.
According to this reaction; H2S(aq) + Cl2(g) -> S(s) + 2HCI (aq)
- H2S accepts electrons from Cl2 and becomes reduced to S
- Cl2 donates electrons to H2S and becomes oxidized to HCl
Therefore, the oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
Learn more about oxidizing agent at: brainly.com/question/10547418
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I have provided the steps to figure out the number of atoms in the chemical compound.
Answer:
0.00007975 mole
Explanation:
Number of moles can be calculated as; mass of solute/volume of solvent or concentration of solution x volume of that solution.
In this case:
Concentration of solution = 1.45 M
Mass of solvent (water in this case) = 55.0 mg
55.0 mg of water is equivalent to 0.55 ml of water.
Therefore, volume of solution = 0.055 ml
Hence, number of moles of solute = molarity x volume
1.45 x 0.000055 = 0.00007975 mole
Answer:
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Thus, a sodium hydroxide solution has a greater OH– concentration than the same concentration solution of NH3. At the same concentrations, the pH of the NaOH solution is greater (more basic) than the NH3 solution.