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sleet_krkn [62]
3 years ago
7

2. Which of the following is not a physical property of water? It is a colorless liquid. It is composed of hydrogen and oxygen.

Sugar dissolves in it. It has a boiling point of 100°C.
Chemistry
1 answer:
S_A_V [24]3 years ago
7 0

The correct answer is C. Sugar dissolves in it

Hope this helps

-AaronWiseIsBae

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Ipatiy [6.2K]

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it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma

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2 years ago
Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1
anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

m_{O_2}=8.65g-8.00g=0.65g

Learn more:

  • brainly.com/question/14502981
  • brainly.com/question/14236219
3 0
2 years ago
How many grams of NO can be produced if 204 g of NO2 is mixed with 58.1 g of H2O?
Goshia [24]

Answer:

44.4 grams of NO can be produced

Explanation:

Step 1: Data given

Mass of NO2 = 204 grams

Molar mass NO2 = 46.0 g/mol

Mass of H2O = 58.1 grams

Molar mass H2O = 18.02 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 204 grams / 46.0 g/mol

Moles NO2 = 4.43 moles

Step 4: Calculate moles H2O

Moles H2O = 58.1 grams / 18.02 g/mol

Moles H2O = 3.22 moles

Step 5: Calculate limiting reactant

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

NO2 is the limiting reactant. It will completely be consumed (4.43 moles). H2O is in excess. there will react 4.43 /3 = 1.48 moles. There will remain 3.22 - 1.48 = 1.74 moles

Step 6: Calculate moles NO

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 4.43 moles NO2 we'll have 4.43/3 = 1.48 moles NO

Step 7: Calculate mass NO

Mass NO = 1.48 moles * 30.01 g/mol

Mass NO = 44.4 grams

44.4 grams of NO can be produced

3 0
3 years ago
A student is investigating the effect of concentration on the colour of a solution of copper sulfate.She wished to make up 250cm
IrinaK [193]

Answer:

79.8g/dm³

Explanation:

As you can see, the solution in the problem contains 0.5 moles of copper sulfate per dm³. To solve this question we must convert these moles to grams using its molar mass (Molar mass CuSO4 = 159.609g/mol) as follows:

0.5mol CuSO4/dm³ * (159.609g/mol) =

<h3>79.8g/dm³</h3>
3 0
3 years ago
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