Answer:
The three major types of bond are ionic, polar covalent, and covalent bonds. Ionic occurs majorly between metals and non-metals, which allows sharing of electrons to form an ionic compound. Whereas covalent bonding calls for complete transfer of electrons between atoms. Polar covalent bonds have unequaly shared electron-pair between two atoms.
Explanation:
a. Cu (Copper)-<em> ionic bonding
</em>
b. KCl (Potassium Chloride)
- <em>ionic bonding
</em>
c. Si (Silicon)
- <em>covalent bonding
</em>
d. CdTe (Cadmium Telluride)
- <em>polar covalent bonding
</em>
e. ZnTe (Zinc Telluride)- <em>polar covalent bonding
</em>
B. 1
Because the subscript is multiplying times the NO
Answer:
Cu
Explanation:
We can use oxidation numbers to figure out what is happening with the electrons.

The oxidation number of Cu increases from 0 to +2 in Cu(NO₃)₂. The copper has gained two positive charges, so it has lost two electrons. It has been oxidized, so it is the reducing agent.
NO₃⁻ is wrong. The oxidation number of N decreases from +5 in NO₃⁻ to +4 in NO₂, so it has been reduced. It is the oxidizing agent.
Cu(NO₃)₂ and NO₂ are wrong. They are the products of the reaction. They cannot be either oxidizing or reducing agents in this reaction