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lesya [120]
3 years ago
11

The two most common eating disorders are anorexia nervosa and bulimia what percentage of American adolescents have experienced a

norexia nervosa or bulimia
Physics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer:

2.7%,Almost three percent of adolescents

Explanation:

The two most common eating disorders are anorexia nervosa and bulimia what percentage of American adolescents have experienced anorexia nervosa or bulimia

The National Institute of Mental Health reports that 2.7% of teens, ages 13-18 years old, struggle with an eating disorder.Almost three percent of adolescents ages 13-18 are diagnosed with an eating disorder. Generally, adolescent girls are at a higher risk for developing an eating disorder than are boys.Eating disorders are a daily struggle for females and  males in the United States in which It is estimated that 1.0%

Four out of ten  individuals have either personally experienced an eating disorder or know someone who has

Hoochie [10]3 years ago
4 0

Answer:

2.7% of American adolescents

Explanation:

This information is based on the diagnostic interview data from National Comorbidity Survey Adolescent Supplement (NCS-A), shows that the lifetime prevalence of eating disorders among U.S. adolescents aged 13 to 18 years is 2.7 %

The statistics equally said that eating disorders that females wer twice more likely to suffer from it than males (females (3.8%) ,males (1.5%)). This eating disorders included anorexia nervosa, bulimia nervosa, and binge eating disorder

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A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision
Nimfa-mama [501]

Answer:

Δ KE =  249158.6 kJ  

Explanation:

given data

Truck mass  M =  1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum  that is express as

Mu = (M+m) V     .......................1

put here  value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy  will be here

Δ KE =   \frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2         .................2

put here value and we get

 Δ KE = \frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2  

solve it we get

Δ KE =  249158.6 kJ  

6 0
3 years ago
Which of the five themes of geography would a person most likely use to study the importation of Chinese goods into the United S
Morgarella [4.7K]
B. Movement would be the correct answer.
7 0
2 years ago
A motorboat heads due east at 16 m/s across a river that flows due south at 9.0 m/s. a.) What is the resultant velocity of the b
alukav5142 [94]

Answer:

a)V=18.35 m/s (South -East)

b) t =7.41 m/s

c)D= 66.70 m

Explanation:

Given that

Velocity of boat in east direction = 16 m/s

Velocity of river = 9 m/s

a)The resultant velocity V

V=\sqrt{16^2+9^2}\ m/s

V=18.35 m/s (South -East)

b)

We know that

Distance = Velocity x time

Lets t time takes to cross the river

136 = 18.35 x t

t =7.41 m/s

c)

   The distance covered downstream  

We know that

Distance = Velocity x time

t= 7.41 s

D= 7.41 x 9 m

D= 66.70 m

3 0
2 years ago
What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates
34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance C_{0} = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 \times 10^{4} V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

             V = Ed

Now,  

              Q = CV

or,           Q = C \times Ed

Therefore, substitute the values into the above formula as follows.

              Q = C \times Ed

                  = 8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})

                  = 2.55 \times 10^{-10} C

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is 2.55 \times 10^{-10} C.

3 0
3 years ago
When a heart artery is clogged and the heart muscle dies, the condition is _______________ ischemia.
3241004551 [841]

the answer is Cardiac ishemia

3 0
3 years ago
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