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lesya [120]
3 years ago
11

The two most common eating disorders are anorexia nervosa and bulimia what percentage of American adolescents have experienced a

norexia nervosa or bulimia
Physics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer:

2.7%,Almost three percent of adolescents

Explanation:

The two most common eating disorders are anorexia nervosa and bulimia what percentage of American adolescents have experienced anorexia nervosa or bulimia

The National Institute of Mental Health reports that 2.7% of teens, ages 13-18 years old, struggle with an eating disorder.Almost three percent of adolescents ages 13-18 are diagnosed with an eating disorder. Generally, adolescent girls are at a higher risk for developing an eating disorder than are boys.Eating disorders are a daily struggle for females and  males in the United States in which It is estimated that 1.0%

Four out of ten  individuals have either personally experienced an eating disorder or know someone who has

Hoochie [10]3 years ago
4 0

Answer:

2.7% of American adolescents

Explanation:

This information is based on the diagnostic interview data from National Comorbidity Survey Adolescent Supplement (NCS-A), shows that the lifetime prevalence of eating disorders among U.S. adolescents aged 13 to 18 years is 2.7 %

The statistics equally said that eating disorders that females wer twice more likely to suffer from it than males (females (3.8%) ,males (1.5%)). This eating disorders included anorexia nervosa, bulimia nervosa, and binge eating disorder

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When a sideways force acts on a moving object, what effect does it have?
My name is Ann [436]

Answer:

it makes the object speed increase, decrease and change the direction of the object.

Hope it helps!

6 0
3 years ago
Two wires A and B with circular cross-section are made of the same metal and have equal lengths, but the resistance of wire A is
Nesterboy [21]

Answer:

r₁/r₂ = 1/2 = 0.5

Explanation:

The resistance of a wire is given by the following formula:

R = ρL/A

where,

R = Resistance of wire

ρ = resistivity of the material of wire

L = Length of wire

A = Cross-sectional area of wire = πr²

r = radius of wire

Therefore,

R = ρL/πr²

<u>FOR WIRE A</u>:

R₁ = ρ₁L₁/πr₁²   -------- equation 1

<u>FOR WIRE B</u>:

R₂ = ρ₂L₂/πr₂²   -------- equation 2

It is given that resistance of wire A is four times greater than the resistance of wire B.

R₁ = 4 R₂

using values from equation 1 and equation 2:

ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²

since, the material and length of both wires are same.

ρ₁ = ρ₂ = ρ

L₁ = L₂ = L

Therefore,

ρL/πr₁² = 4ρL/πr₂²

1/r₁² = 4/r₂²

r₁²/r₂² = 1/4

taking square root on both sides:

<u>r₁/r₂ = 1/2 = 0.5</u>

6 0
4 years ago
The label has been scratched off a tuning fork and you need to know its frequency. From its size, you suspect that it is somewhe
bonufazy [111]

Answer:

255 Hz

Explanation:

With 5 beats per second with the 250 Hz fork, we know the unknown fork is either 250 - 5 = 245Hz or 250 + 5 = 255 Hz

With 15 beats per second with the 270 Hz fork, we know the unknown fork is either 270 - 15 = 255Hz or 270 + 15 = 285 Hz (most people would have a hard time discerning 15 beats per second... 5 per second is hard enough)

As 255 is the common frequency, it is the one selected.

3 0
3 years ago
How the Law of Conservation of Matter is supported by the experimental demonstrations?
Delvig [45]
The law of conservation of matter states that matter cannot be created nor destroyed. It can only be transformed from one form to another. To state an example where this is shown, let's say a piece of paper is burning. Not having a scientific background, you would say that the matter is being destroyed. But in reality, the paper is simple being transformed to ash, carbon dioxide, and water vapor. Overall, the total mass would still remain the same.
6 0
3 years ago
The half-life of cobalt-60 is 5.26 years. If 50 g are left after 15.8 years, how many
PtichkaEL [24]

Answer:

400 g

Explanation:

The computation of the number of grams in the original sample is shown below:

Given that

half-life = 5.26 years

total time of decay = 15.8 years

final amount = 50.0 g

Now based on the above information  

number of half-lives past is

=  15.8 ÷ 5.26

= 3 half-lives

Now

3 half-lives = 1 ÷ 8 remains = 50.0 g

So, the number of grams would be

= 50.0 g × 8

= 400 g

4 0
2 years ago
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