Answer:
Δ KE = 249158.6 kJ
Explanation:
given data
Truck mass M = 1560 Kg
Truck initial speed, u = 28 m/s
mass of car m = 1070 Kg
initial speed of car u1 = 0 m/s
solution
first we get here final speed by using conservation of momentum that is express as
Mu = (M+m) V .......................1
put here value we get
1560 × 28 = (1560 + 1070 ) V
solve it we get
final speed V = 16.60 m/s
and
Change in kinetic energy will be here
Δ KE =
.................2
put here value and we get
Δ KE =
solve it we get
Δ KE = 249158.6 kJ
Answer:
a)V=18.35 m/s (South -East)
b) t =7.41 m/s
c)D= 66.70 m
Explanation:
Given that
Velocity of boat in east direction = 16 m/s
Velocity of river = 9 m/s
a)The resultant velocity V

V=18.35 m/s (South -East)
b)
We know that
Distance = Velocity x time
Lets t time takes to cross the river
136 = 18.35 x t
t =7.41 m/s
c)
The distance covered downstream
We know that
Distance = Velocity x time
t= 7.41 s
D= 7.41 x 9 m
D= 66.70 m
The given question is incomplete. The complete question is as follows.
A parallel-plate capacitor has capacitance
= 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.
What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed
V/m?
Explanation:
It is known that relation between electric field and the voltage is as follows.
V = Ed
Now,
Q = CV
or, Q = 
Therefore, substitute the values into the above formula as follows.
Q = 
=
= 
Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is
.