A rocket explodes as it begins to launch. As a result, the rocket is destroyed
2 answers:
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Solution :
Given :
Mass attached to the spring = 4 kg
Mass dropped = 6 kg
Force constant = 100 N/m
Initial amplitude = 2 m
Therefore,
a).
= 10 m/s
Final velocity, v at equilibrium position, v = 5 m/s
Now,
A' = amplitude = 1.4142 m
b).
m' = 2m
Hence,
c).
Therefore, factor
Thus, the energy will change half times as the result of the collision.
Answer:
The impulse on the object is 60Ns.
Explanation:
Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.
F = m a
F = m()
⇒ Ft = m( -
)
where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, is its initialvelocity and
is the final velocity of the object.
Therefore,
impulse = Ft = m( -
)
From the question, m = 3kg, = 0m/s and
= 20m/s.
So that,
Impulse = 3 (20 - 0)
= 3(20)
= 60Ns
The impulse on the object is 60Ns.