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2 years ago

What is the specific heat of an object if it takes 1200 J to raise the temperature of a 20 kg object by 6 degrees C?

Physics

1 answer:

ch4aika [34]2 years ago

5 0

Answer:

$c=10\ J/kg^{\circ} C$

Explanation:

Given that,

Heat required, Q = 1200 J

Mass of the object, m = 20 kg

The increase in temperature, $\Delta T=6^{\circ} C$

We need to find the specific heat of the object. The heat required to raise the temperature is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{1200}{20\times 6}\\\\c=10\ J/kg^{\circ} C$

So, the specific heat of the object is $10\ J/kg^{\circ} C$ .

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Three balls with the same radius 18 cm are in water. Ball 1 floats, with half of it exposed above the water level. Ball 2, with

Kay [80]

Answer:

(a)

4) The magnitude of buoyancy force is equal to that of ball's weight

(b) The magnitude of buoyancy force is larger than that of ball's weight. The tension on second ball is 158 newtons

Explanation:

Newton's third law of motion states that forces always occurs in pairs. For every reaction there is an equal an opposite reaction. For Ball 1 the magnitude of buoyancy force is equal to that of ball's weight. Buoyancy force works against the gravity. Ball 2 and ball 3 have same buoyancy force. The buoyancy force for ball 2 and ball 3 is larger than that of ball's weight.

Tension = Wb - fb

Tension for Ball 2 = 1000 - 842 = 158 newtons

Tension for Ball 3 = 1000 - 1218 = -218 newtons

3 0

2 years ago

An object has a kinetic energy of 14 J and a mass of 17 kg , how fast is the object moving?

lisabon 2012 [21]

$v ^{2}$ = Joules ÷ (0.5×Kilograms)

14J ÷ 8.5 = 1.64705882

Remember, 1.64705882 = v², so we need to find the square root.

The square root of 1.64705882 is 1.283377894464448

Hope this helps!

6 0

3 years ago

Read 2 more answers

Lake Baikal in Siberia has a maximum depth of 1642 m. What is the water

Veseljchak [2.6K]

Explanation:

Fluid gauge pressure is:

P = ρgh

where ρ is the fluid density and h is the depth of the fluid.

P = (1000 kg/m³) (9.8 m/s²) (1642 m)

P = 16,091,600 Pa

Rounded to four significant figures, the gauge pressure is 16.09 MPa.

3 0

3 years ago

Using Excel, or some other graphing software, plot the values of y as a function of x. (You will not submit this spreadsheet. Ho

Evgesh-ka [11]

Answer:

a) > x<-c(1,2,3,4,5)

> y<-c(1.9,3.5,3.7,5.1,6)

> linearmodel<-lm(y~x)

And the output is given by:

> linearmodel

Call:

lm(formula = y ~ x)

Coefficients:

(Intercept) x

1.10 0.98

b) $y = 0.98 x +1.10$

And if we compare this with the general model $y = mx +b$

We see that the slope is m= 0.98 and the intercept b = 1.10

Explanation:

Part a

For this case we have the following data:

x: 1,2,3,4,5

y: 1.9,3.5,3.7,5.1, 6

For this case we can use the following R code:

> x<-c(1,2,3,4,5)

> y<-c(1.9,3.5,3.7,5.1,6)

> linearmodel<-lm(y~x)

And the output is given by:

> linearmodel

Call:

lm(formula = y ~ x)

Coefficients:

(Intercept) x

1.10 0.98

Part b

For this case we have the following trend equation given:

$y = 0.98 x +1.10$

And if we compare this with the general model $y = mx +b$

We see that the slope is m= 0.98 and the intercept b = 1.10

7 0

3 years ago

A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time

baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

$i = \frac{q}{t}$

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

$i = increased$

So correct answer will be

B. The current increases.

4 0

3 years ago