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Greeley [361]
3 years ago
7

write a program in which the user can enter X amount of numbers. Once the user has enter 10 positive numbers, the user may not e

nter anymore numbers. Then the program should display the sum of those 10 positive number and also display the 10 positive numbers.
Computers and Technology
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

The following code is in C++.

#include <iostream>

using namespace std;

int main() {

   int a[10],sum=0;//declaring an array and initialized variable sum with value 0.

   cout<<"Enter the numbers"<<endl;

   for(int i=0;i<10;i++)

   {

       cin>>a[i]; //taking input of 10 integers.

   }

   for(int i=0;i<10;i++)

   {

       sum=sum+a[i];//finding the sum..

   }

   cout<<"The sum is : "<<sum<<endl<<"The numbers entered are "<<endl;

   for(int i=0;i<10;i++)

   {

       cout<<a[i]<<" ";//displaying the elements.

   }

return 0;

}

Output:-

Enter the numbers

1 2 3 4 5 6 7 8 9 10

The sum is : 55

The numbers entered are  

1 2 3 4 5 6 7 8 9 10

Explanation:

I have taken an array of size 10 so that no more than 10 integers could fit in it.After that taking the input from the user prompting 10 integers using the for loop.After that finding the sum.Then printing the sum and the numbers entered.

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Answer:

Ans. Ready to download, please see the file attached to this document

Explanation:

Note. Consider changing the cell in yellow, does not make sense, it could be 10100 instead of 1010

Hi, to design this sheet, I also used the and(...) function of MS excel, in which you declate that in order to select a certain answer, 2 or more conditions must be true, in our case, if a purchase is up to 1000, the price would be $1010 (consider changing this value, maybe to 10100), if the purchase is more than 1000 and less than 5000, the price is $9,509.50, and if is more than 5000 units, the price would be $5,5005.50.

Please check the formula for further clarifications.

Best of luck.

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write a c++ program that reads from the user a positive integer (in a decimal representation), and prints its binary (base 2) re
Vesna [10]

Answer:

The program to this question can be described as follows:

Program:

#include <iostream> //defining header file

using namespace std;

int main() //defining main method

{

int x1,rem,i=1; //defining integer variable

long Num=0;// defining long variable

cout << "Input a decimal number: "; // print message

cin >> x1; //input value by user

while (x1!=0) //loop for calculate binary number

{

//calculating binary value    

rem= x1%2;

x1=x1/2;

Num =Num +rem*i;//holding calculate value

i=i*10;

}

cout <<Num;//print value

return 0;

}

Output:

Input a decimal number: 76

1001100

Explanation:

In the above code, four variable "x1, rem, i, and Num" is declared, in which three "x1, rem, and i" is an integer variable, and one "Num" is a long variable.

  • In the x1 variable, we take input by the user and use the while loop to calculate its binary number.
  • In the loop, first, we check x1 variable value is not equal to 0, inside we calculate it binary number that store in long "Num" variable, after calculating its binary number the print method "cout" is used to prints its value.  
5 0
3 years ago
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