2 years ago

How many electron pairs does chlorine have?

Physics

1 answer:

I am Lyosha [343]2 years ago

3 0

Answer:

10- in 5 pairs

Explanation:

I just did the quiz

You might be interested in

A 15 kilogram mass is traveling with a velocity of 2.7m/s. What is the object's kinetic energy?

Usimov [2.4K]

Answer:

KE=1/2*m*v^2

KE=1/2*15*2.7^2

KE=54.675 J

Explanation:

4 0

2 years ago

A=vf-vi/t is the equation for calculating the acceleration of an object. write out the relationship shown in the equation using

Lelechka [254]

Basically it is the difference in velocity divided by the time it takes to make that change.

3 0

2 years ago

Explain why Earth and other planets were not solid when they formed during the beginning of the Precambrian, approximately 4,600

alexandr402 [8]

earth still is not solid ... core is molten ... volcanoes, sea is liquid

at v v v beginning was gas ????

5 0

2 years ago

Ozone in the upper atmosphere absorbs energy in the 210-230 nmnm range of the spectrum. In what region of the electromagnetic sp

kifflom [539]

Answer:

Ultraviolet

Explanation:

The electromagnetic spectrum is divided into a number of parts. One of which is the ultraviolet region. The ultraviolet region is found between the 100 nm - 400 nm band of the electromagnetic spectrum. From the range we just stated now, we can see for certainty that the given range 210 nm - 230 nm lies inside of the 100 nm c 400 nm of the electromagnetic spectrum, that of which is the ultraviolet region.

5 0

2 years ago

You lift a 25-kg child 0.80 m, slowly carry him 10 m to the playroom, and finally set him back down 0.80 m onto the playroom flo

maksim [4K]

To solve this problem we will apply the work theorem which is expressed as the force applied to displace a body. Considering that body strength is equivalent to weight, we will make the following considerations

$\text{Mass of the child} = m = 25kg$

$\text{Acceleration due to gravity} = g = 9.81m/s^2$

$\text{Height lifted} = h = 0.80m (Upward)$

Work done to upward the object

$W = mgh$

$W = (25)(9.81)(0.8)$

$W = 196.2J$

Horizontal Force applied while carrying 10m,

$F = 0N$

$W = 0J$

Height descended in setting the child down

$h' = -0.8m (Downwoard)$

$W = mgh'$

$W = (25)(9.81)(-0.80)$

$W = -196.2J$

For full time, assuming that the total value of work is always expressed in terms of its symbol, it would be zero, since at first it performs the same work that is later complemented in a negative way.

6 0

3 years ago