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spin [16.1K]
3 years ago
5

A test car starts from rest on a horizontal circular track of 85-m radius and increases its speed at a uniform rate to reach 115

km/h in 13 seconds. Determine the magnitude a of the total acceleration of the car 11 seconds after the start.
Physics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

27.03 m/s.

Explanation:

vo = 0 m/s

vi = 115 km/h

Converting to m/s,

115 km/h * 1000 m/1 km * 1 h/3600 s

= 31.94 m/s.

Using equation of motion,

vi = vo + at

a = 31.94/13

= 2.46 m/s^2

After t = 11 s,

vi = 2.46 * 11

= 27.03 m/s.

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A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. Long
tino4ka555 [31]

Answer:

A) equal to the battery's terminal voltage.

Explanation:

When the capacitor is fully charged after long hours of charging , its  potential becomes equal to the emf of the battery and its polarity is opposite to that of battery . Hence net emf becomes equal . The capacitor itself becomes a battery which is connected in the circuit with opposite polarity . This results in the net emf and  current becoming zero . There is no charging current when the capacitor is fully charged .

4 0
3 years ago
Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge
asambeis [7]

Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

E =\dfrac{kq}{r^2}

q =\dfrac{Er^2}{k}

inserting all the values

q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}

      q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

4 0
3 years ago
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
White raven [17]

Answer:

400ft.    32ft/s       -32ft/s

Explanation:

In reality the gravitational acceleration is 9.81 so the quadratic coefficient of the function should be 9.81/2

Anyway for the sake of assumtion let us takes=160t-16t^2

 

ds/dt=160-32t=0

 

t=160/32= 5 seconds.

s=160*160/32-16*(160/32)^2= 400 mts

 

 

s=384 mts

160t-16t^2=384

i.e

16t^2-160t+384=0

 

t^2-10t+24=0

(t-6)(t-4)=0

t=[4,6]

we have to take t=4 because it is all the up i.e <5

 

velocity =v=ds/dt=160-32t

 

v=160-32*4=32 ft/sec still going up

 

for all the way down take t=6 whuch is >5

 

v=160-6*32=-32 ft/sec (falling down!!!)

6 0
3 years ago
Determine the energy, in electron volts, of an emitted photon when an electron transition from n=3 to n=2 occurs
tensa zangetsu [6.8K]
Give me some answer choices and i will be happy to help
7 0
3 years ago
Diferencia entre transferencia y transformación de energía. Da ejemplos de cada caso.
Firdavs [7]

Answer:

La transformación de energía es un proceso en el que la energía se intercambia entre un sistema y el medio ambiente en al menos dos formas de energía diferentes entre sí. Por ejemplo, un panel solar convierte la energía lumínica en energía eléctrica.

En cambio, en la transferencia de energía, esta no cambia su forma sino que es transmitida de un cuerpo a otro. El ejemplo más claro es el de la fogata, que transmite calor al medio ambiente a través de radiación.

6 0
3 years ago
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