Taste and smell would be considered
1 answer:
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Answer:
a. 150 J
b. 150 J
c. 0 J
d. 0 J
Explanation:
The given parameters are;
The horizontal force with which the man pulls the canister, F = 50 N
The distance he moves the vacuum cleaner, d = 3.0 m
a. Work done, W = Force applied, F × Distance moved by the force, d
Therefore, for the work done by the 50 N force on the canister, we have;
W = 50 N × 3.0 m = 150 N·m = 150 J
b. Given that he pulls the canister at a constant speed, we have;
The acceleration of the canister, a = 0 m/s²
Therefore, the net force on the canister, = F -
= m × a
Where;
m = The mass of the canister
a = The acceleration of the canister
F = The applied force = 50 N
= The force of friction
∴ = m × a = m × 0 m/s² = 0 N
Therefore;
= F -
= 0 N
From which we have;
F = = 50 N (The applied force, F is equal to the force of friction,
The work done by friction = The force of friction × The distance in which the force of friction acts
∴ The work done by friction = × d - 50 N × 3.0 m = 150 J
The work done by friction = 150 J
c. The normal force, N acts perpendicular to the force of friction
The distance the canister moves in the perpendicular direction, = 0 m
∴ The work done by the normal direction = N × = N × 0 m = 0 J
The work done by the normal direction = 0 J
d. The vacuum weight, W, acts on the same line as the normal force but in the opposite direction to the normal force, N
Therefore, the weight, W, acts perpendicular to the line of motion of canister
The distance the canister moves in the direction of the weight, = 0 m
Therefore, the work done by the weight = W × = W × 0 m = 0 J
The work done by the weight = 0 J
Answer:
d = 5.10 m
Explanation:
As we know that here on the plane of the inclined there is no frictional force
So in these cases we can say that total mechanical energy will always remains conserved
so here we can say that
spring potential energy = gravitational potential energy of the block
as we know from the formula
now plug in the values in it
now as we know that the angle of inclination is 60 degree and height raised is 4.42 m
so here maximum distance moved along the inclined plane will be